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How about
outfile=${outfile%_v2}?

man bash: "Parameter Expansion" is a good reading for this...

There might be a # missing - try
outfile="${infile%%/save*}${infile#*save}"

There are several problems with this: first, the "{}" placeholder for the found filename can only be used ONCE in a single -exec clause.

Second: you are calling poor sed for every file you find....

With sed
echo "DBPATH=/some/path/database/db" | sed 's#.*=##; s#/[^/]*$##'


---------- Post updated at 11:52 AM ---------- Previous update was at 11:31 AM ----------

With expr
expr...

Hello ejianu,

Please try following(sorry I didn't see you don't need db also).

echo "DBPATH=/some/path/database/db" | nawk '{sub(/.*=/,X,$0);match($0,/\/.*\//);print...

Hello ejianu,

On a Solaris/SunOS system, change awkto /usr/xpg4/bin/awk , /usr/xpg6/bin/awk, or nawk.

Thanks,
R. Singh

Hello Ejianu,

Following may help you in same.

echo "DBPATH=/some/path/database/db" | awk '{sub(/.*=/,X,$0);print}'


Thanks,
R. Singh

A different approach that I had prepared in case you show your doing 1st - nevertheless - maybe helpful too. Single steps; the test for 11 shouldn't be the problem:

# cat blafile
# set -A arrayA...

change to this ;)
sed -e ':a' -e '$!N;s/\n/,/;ta'