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perl -ne '/(\d+)/; if ( $1 >= 6 && $1 <= 10 ){print}' temp.txt
perl -ne '/(\d+)/; if ( $1 >= 11 && $1 <= 100 ){print}' temp.txt
perl -ne '/(\d+)/; if ( $1 >= 101 ){print}' temp.txt

$ nawk '{ if($2<10){print $0 > "1.txt"}else{if($2<100){print $0 >"2.txt"}else{print $0 > "3.txt"}}}' test


$ cat 1.txt
UDUYDS 8
UIUHKK 6


$ cat 2.txt
KJKAJK 89...

It might be easier using something like this for group 2 for example:

$> awk '$2 >= 11 && $2 <= 100' infile
KJAJAK 100
KJKAJK 89
JOIJOI 21
JDKDJL 12

awk '$2>=6&&$2<=10' file
awk '$2>=11&&$2<=100' file
awk '$2>=101' file

Assuming your numbers are in the file "line.numbers" like so
3
4
7
perl -lne ' ...

Check whether you have any control m characters in your script

cat -vet sql.sh

From grep:Anchoring
The caret ^ and the dollar sign $ are meta-characters that respectively match the empty string at the beginning and end of a line.
So you need to use:
grep -w ^531250 file

grep '^531250' file

From the grep manual:
The test is that the matching substring must either be at the beginning of the line, or preceded by a non-word constituent character.
Similarly, it must be either at the end...

while read line1
do
line2=`grep "$line1" file2`
if [ ! -z "$line2" ] ; then
echo "$line2" >> file3
else
echo "" >> file3
fi
done < file1