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You specified just the MIME header, but the file is not attached!

Here is an example using uuencode for encoding:
echo "Content-Type: image/png"
echo "Content-Disposition: attachment;...

You didn't actually include the contents of the .png in there.

First try:
(
echo "From: $FROM"
echo "To: $TO"
echo "MIME-Version: 1.0"
echo "Subject: $SUBJECT"
echo 'Content-Type:...

try this..


outputFile="/tmp/out.html"
attachFile="/tmp/attach.html"
(
echo "From: abc@abc.com"
echo "To: abc@abc.com"
echo "Subject: Test"
echo "Mime-Version: 1.0"
echo 'Content-Type:...

Well you could fetch all the users with a non blank cidx first:

ldapsearch -h server_domain_name -p 389 -D "uid=user,ou=appadm,o=ent" -w PaB -b "ou=roles,o=ent" '(&objectClass=user)(cidx=*))'...

awk -F'|' '!(key[$1$2]){print;key[$1$2]=1}' yourfile

Well,
ignoring the timestamp in the last column:

awk -F\| '!key[$1, $2]++' infile

Your "^I" is the "<tab>" character.

If you are using "vi":
:%s/<tab>//g

If you are in the unix prompt:
sed 's/<tab>//g' inp_file

Try this,

sed -n '/TO/,/PRO/p' inputfile | sed 's/TO//g;s/PRO/-------/g'

Hi
When I run, I am getting the right output.

Guru

Try this,

perl -nle 's/^(\d+\s+|\d)(\D+)/\2 \1/g;print $_;' inputfile

Would be ok if the output order doesn't matter :
sed 's/\s*###\s*//;s/^\s*//' infile | awk '/^\s*$/{next}!/^[0-9][0-9]*/{B[x]=B[x]?B[x]","$0:$0}/^[0-9][0-9]*/{x=$1;A[$1]=$1" "}END{for(i in A)print...

awk '/<s>/{next} /<\/s>/{print s;s="";next} {s=length==1?s $0:s?s FS $0:$0}' file
Explanation:
/<s>/{next} | Skip the line with <s>

/<\/s>/{print s;s="";next} | If the line matches with </s>...

Yes it is probably too cryptic, which is because it was a bit of a challenge to see if it could be done shorter, all in good fun ;) but quite a bit less readable then Radoulov's version..

Anyway....

With the GNU date:
LIMIT=$(date -d '-8 days' '+%Y/%m/%d')
while IFS='|'; read D L
do [[ $D > $LIMIT ]] && echo "$D|$L"
done < infile
awk:
awk -F'|' -vD=$(date -d '-8 days' '+%Y/%m/%d') '$1 > D'...

Somrthing like this,

awk -F, '{printf "%s,%.2f\n",$0,($5/$8*100)}' infile

awk -F, '{printf "%s,%s",$0,substr($5/$8*100,2,3)}' urfile

2010-08-18,10,24,.09751,39,7,14872,26732,.14

sed -n "N;N;s/\n/|/g;p" file

---------- Post updated at 02:02 PM ---------- Previous update was at 01:04 PM ----------

paste -d"|" - - - < file

Or

awk ' { ORS=( NR % 3 == 0 ? "\n" : "|" )...

Hi



awk '/id-number/{h=$0" ";i=0;next} NF{printf h;print;i++;next;}{if (i==0) {printf h;print;}}1' infile


Guru.

Welcome to the forum. Here is one possibility:
awk '/id-number/{h=$0" ";next} NF{printf h}1' infile