Search Results

the usual paradigm...

awk 'FNR==NR{m[$4];next} $4 in m' mappingFile sourceFile

old_date=`echo $static_date | awk '{print substr($0,1,4)-3""substr($0,5)}'`
future_date=`echo $static_date | awk '{print substr($0,1,4)+2""substr($0,5)}'`

static_date=20120529
old_date=$((static_date - (3 * 10000)))
future_date=$((static_date + (2 * 10000)))

$ awk '{printf("%s%s",$0,NR%3?",":"\n")}' input
a,b,c
d,e,f
g,h,i
j,

$ paste -d, - - - < infile
a,b,c
d,e,f
g,h,i
j,,

awk '{ORS=NR%3?",":"\n"}' filename

#! /bin/bash
while read x
do
mapped=`grep $x output`
echo ${mapped#*|}
done < input_string.txt

I think this is closer to what you want, and far more efficient than running grep 9,000 times to process 9,000 different matches. It loads the entire mapping file in at once into an associative...

download and install the shell compiler shc:

Download shc 3.8.6 for Linux - shc project is a generic shell script compiler. - Softpedia...

I hope this will anwer your query


awk 'NR==FNR{a[$1]=$1;next} {for(v in a){ print v","$0 | "sort -n -k1" }}' file1 file2

I think your regex isn't working. You can make it a lot simpler.

$ diff file1.txt file2.txt | awk '/^</ { printf("%-20s\n", $2) }'

"print" is a KSH-only thing. It's not on BASH because BASH is not KSH. Use 'echo', which truly is everywhere, in binary and builtin forms.

Or printf, with its more advanced features.

Or if...

By overwriting it with the temp file.

awk, and nearly any stream-based utility, does not edit "in place". If you try to write to the same file at the same time you'll destroy it.

Try: awk -vd=`date +%Y%m%d` -F"|" -vOFS="|" '{$6=d}1' file

[ $date -gt `date -d "+6 days" +%Y%m%d` ]

I assume you can "substr" date from each line successfully yourself.

Please use code tags next time, thanks.


pos=$(expr index $name [oO])

printf "%-20s%-40s%-20s\n" "$a" "$b" "$c"