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Hi,
Try:
grep '[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]' file_all.txt | sort

But in your file, just:
grep '/' file_all.txt | sort

Regards.

@Chubler, what about around year changes?

Looks like your on Fedora so you should have GNU date:

set -- $(date -d "-30 days" "+%Y %m %d %p %I %M")
awk -vY=$1 -vm=$2 -vd=$3 -vp=$4 -vI=$5 -vM=$6 '
$3>Y||
$3==Y&&$1>m||...

Should all be good, comparison is Y M D AM H M in that order.

Try this:

set -- $(perl -MPOSIX -le'@a=localtime;$a[3]-=30;print strftime "%Y %m %d %p %I %M",@a')
awk -vY=$1 -vm=$2 -vd=$3 -vp=$4 -vI=$5 -vM=$6 '
$3>Y||
$3==Y&&$1>m||
$3==Y&&$1==m&&$2>d||...

Try:
find /allcode/mainld/process/recenttmp -type f ! -name "* *"

Please.. look into answer once again :)

Regards,
Akshay

Hello,

Following may help you.



awk '!a[$6]++' file_name



Output will be as follows.


03/17/2014 10:35 AM 618 Admin\vick abc_ xyz1_bc12_20140312_c.xlsx
03/17/2014 ...

awk '{fname = "";
for(i = 6; i <= NF; i++)
{fname = (fname == "") ? $i : (fname OFS $i)};
if(a[fname]++ == 0) {print $0}}'