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grep is going to show the whole line unless the c or s option is used. You could used sed to insert escape sequences around your searched for term to make the first one stand out (apply a color or...

How about
awk '
NR == FNR {SRCH = SRCH DL $0
DL = "|"
next
}
match ($0, SRCH){print substr ($0, RSTART, RLENGTH)
}
'...

Hi.

There is a code, peg, that may do what you desire: multiple patterns of PERLRE expressions. Using the pattern from disedorgue and an augmented data file, a demo is:
#!/usr/bin/env bash

#...

Well, if you're rewriting from scratch anyway, you could have a file full of awk expressions, like:

# Do NOT print line if this regex matches
/regex1/ { next }

# print line if it contains this...

Greedy matching is doing you in. All "(?!foobuzz)..." needs to find is one spot before user1 which doesn't start in 'f' and its condition is satisfied. The .* after it swallows everything. So it...

Hi, with grep:
$ cat gr.txt
2015-04-08 19:04:55,926|xxxxxxxxxx| |foobar| |INFO |REQUEST|UserID1:42 | yeah
2015-04-08 19:04:56,157|yyyyyyyyyy| |foobuzz| |INFO...

With files that big performance considerations are perhaps vital, so take the following with a grain of salt. I have no file that big to test it.

Instead of using "-f <file>" to read the file...

Try this...

./output.sh | xargs ./input.sh


--ahamed