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Try:
awk -F@ '!A[$0=$2]++' file

Try:
awk -FFROM: 'NF>1{print $2}' file
sed -n 's/.*FROM://p' file

awk 'NF && /open[ \t]*$/{sub(/[ \t]*\(\?\).*/,"");print "Port opened for",$0;next}
NF && /Connection refused[ \t]*$/{sub(/[ \t]*\(\?\).*/,"");print "Port cannot be reached for",$0}'...

What happens when you set NFS_CLIENT_VERSMAX=3 in /etc/default/nfs and restart your NFS server?

I've experienced this problem in the past and remember having to fight it.

I recommend that you ease all security until you make is work and then tighten up afterwards. I can confirm that it can...

The cron deamon will still have the old clock. You will need to stop it. It may be defined in /etc/inittab as respawn in which case it will start a new one for you.




Robin...

use back tick and check it once again

dt1=`perl -e 'use POSIX;print strftime "%d-%m-%Y-%M",localtime time-86400;'`

redirect your stderr and stdout

0-59 * * * * /var/tmp/r.sh 1>/tmp/out.txt 2>&1

use the absolute path for the files

mv /absolute/path/local0.log local0.log.$dt1
mv /absolute/path/local1.log local1.log.$dt1
mv /absolute/path/local2.log local2.log.$dt1

Post output of: tail -50 /var/cron/log

user@host> (/home/user) $ a=10
user@host> (/home/user) $ vi test.sh
user@host> (/home/user) $
user@host> (/home/user) $
user@host> (/home/user) $ ./test.sh

user@host> (/home/user) $ echo $a...

It is working fine for me.Please check whether your IP is correct and try to FTP manually for that IP.

user@host2> (/home/user) $ cat test.sh
#!/bin/bash
function upload(){
ftp -inv...

function upload(){
ftp -inv $hostname <<EOF
user $user_name $pass_word
put $file_name
bye
EOF
}
This will work. You wrote the function wrong.

you have to use


ftp -inv $hostname
user $user_name $pass_word

I didnt test this. Hope this will work. I have given just a skeleton you need some work to make this work.


upload()
{
ftp $hostname
user $user_name
password $password
put $file_name...

# awk -F"[,%]" '{x=$(NF-1);if(m<x)m=x;s+=x}END{printf "max=%.1f%%\nsum=%.1f\navg=%.1f%%\n",m,s,s/NR}' infile
max=98.5%
sum=1061.7
avg=96.5%Use nawk or /usr/xpg4/bin/awk if running on SunOS/Solaris...

perl -F, -lane 'BEGIN{$max=0;$avg=0;$i} $i++;$F[7]=~s/%//g; $max=$F[7] if($F[7]>$max); $avg+= $F[7];END{print $max;print($avg/$i)}'

Thanks,
MG

Try:
awk '{if ((NR %2)== 1){ f = $2;print $0;} else {printf "%s %s\n",$0,f} }' test.txt

This assumes the alternate occurrance of echo and awk

Give multiple file names seperated by space instead of just 'file'

awk -F, 'BEGIN{max=0;total=0}{if((100-$8) > max){max =(100-$8)};total=total+(100-$8)}END{print max,total/NR}' text.txt

awk -F, '{sub ("%","",$8);sum+=100-$8;if (100-$8>max){max=100-$8}}END{printf "max=%.1f%\navg=%.1f%\n",max,sum/NR}' file

long but effective and easy approach!!
a=`cat filename |awk -F"," '{print $8}' |tr "%" " " |sort |tail -1`
b=`cat filename |awk -F"," '{print $8}' |tr "%" " " |awk '{c +=$1}END{print c}'`
e=`cat...

Another approach:
awk -F"[,%]" '{max=$(NF-1)>max?$(NF-1):max; som+=$(NF-1)}END{print max, som/NR}' file

Try: awk -F, '{sub ("%","",$8);sum+=$8;if ($8>max){max=$8}}END{printf "max=%.1f\%\navg=%.1f\%\n",max,sum/NR}' file

awk -F, 'BEGIN{max=0;total=0}{if($8 > max){max =$8};total=total+$8}END{print max,total/NR}' text.txt