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This looks like a syntax error.
Please re-post the line.


If it is just that the $ sign is a typo, this should lose all output to stdout and stderr from the child script....

1) Is testing whether there is at least on file (-f) in the root directory "/" which matches the pattern "ITF_*.dat". The asterisk is a wild card and the underscore and full stop characters are part...

1. if any files exist that match ITF_*.dat in the root (/) directory.
2. For an absolute path (one beginning with /), will remove the path, leaving just the filename. i.e. removes everything (*)...

Why don't you try the code of my last post ?

Jean-Pierre.

Sorry, I forgot a modification (Assume that WOR is'nt a shell variable):awk '{
if ( substr($0, 392, 1)=="C" )
DOC = substr($0, 28, 15) substr($0, 386, 3);
else
DOC =...

There was type errors in the code of my previous post, they have been edited.

An example with your last sample datas (kam.txt):1 12367 A 1100
2 12367 ...

Try
awk '{
if ( substr($0, 392, 1)=="C" )
DOC = substr($0, 28, 15) substr($0, 386, 3);
else
DOC = substr($0, 28, 18);
print $0 > "WOR/WORK_" DOC ".txt"
}'...

The syntax ${DOC}is valid for shell variables.
Here you are inside an awk program that does'nt accept this syntax.

Modify your script:awk '{
if ( substr($0, 392, 1)=="C" )
DOC =...

awk '{if ($1~/C/) {print > "DOCKEY_" t;next}} {t=$2;print > "DOCKEY_" $2}' urfile

A solution is to do all the work in one awk program (not tested):
awk '
{
if ( substr($0, 392, 1)=="C" )
DOC = substr($0, 28, 15) substr($0, 386, 3)
else
DOC = substr($0, 28,...