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Merry Christmas to All. Peace on Earth and Goodwill toward Everyone

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Hello,

Following may help you.


awk '$1 ~ /G/ {print $0}' file_name



Output will be as follows.


1G /tmp/a/b
2.2G /tmp/c


Thanks,
R. Singh

Assuming the lines are in chronological order within the file and there are no spaces in the file names, try
awk '{A[$NF]=$0} END{for(i in A) print A[i]}' file

Try this,
sed 's/\%//g; s/G//g' text

Regards,
Indu

sort < infile | uniq -c

while read x; do echo "reader='$x' or"; done < inputfile

sed -e "s/^/reader='/g" -e "s/$/' or/g" inputfile

Try this...

sed "s/.*/read='&' or/g;$ {s/or//g}" infile


--ahamed

Try with this ..

printf "Enter start range : " ; read a
printf "Enter end range : " ; read b
sqlplus -s $dbconnect <<-!
whenever sqlerror exit 1
select * from temp_table where rownum >= $a...

Or you can use rsync to do the trick:

rsync -nr --existing dir1/ dir2/

df -h | grep "9[0-9]%"