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awk '{sub("-",X,$0); sum += $0} END {print sum}' file

You didn't answer my question about the length of the longest line in your file! If you have any lines longer than 2048 bytes (including the terminating newline character), nawk may fail.


The...

Making the assumption that that error code is coming from bc, you could try:
awk -F'|' -v dqANDms='["-]' '
BEGIN { f=156
printf("s=0\n")
}
NR > 2 {gsub(dqANDms, "", $f)
...

Assuming that you're using the tail in the command line:
tail -n +2 <File_Name> |nawk -F"|" -v '%.2f' qq='"' '{gsub(qq,"");sa+=($156<0)?-$156:$156}END{print sa}' OFMT='%.5f'
to discard the 1st two...

Hi

{print > "FILE"x;} -> Write every record to the file "FILE"x where x is 1,2,3 and so on. x starts with 1 and gets incremented for every 4 records.

!(NR%4){print "PAGE "x > "FILE"x;x++;} ->...

^M is a carriage return.

You should understand a few things first:

CR = \r = Carriage Return
LF = \n = Line Feed

In DOS, all lines end with a CR/LF combination or \r\n.
In UNIX, all lines...

To find whether a file has a CR or not you can use grep, this should print the lines with a CR:

grep '^M' file1Type <Ctr-v><Ctr-m> to get ^M and not a ^ and an M.

Regards

Hi ,

i got this solution from one of this forum post.


30 17 8-14,22-28 * * [ `date +\%u` -eq 6 ] && /rebootscript



So , will this also reboot the server on 2nd and 4th saturday ?

Hi


$ cat file
1
2
3
4
5
6
7
8
9
10


$ awk '{print > "FILE"x;}!(NR%4){print "PAGE "x > "FILE"x;x++;}END{print "PAGE "x > "FILE"x}' x=1 file

$ cat FILE1
1

Hi

Try doing something like this: https://www.unix.com/shell-programming-scripting/15520-cron-schedule-1st-wednesday-every-month.html...

You can use something like this:

awk 'END { printf "E%03d end\n", c > f }
!(NR % 200) || NR == 1 { if (f) { printf "E%03d end\n", c > f; close(f) }
printf "E%03d start\n", ++c > (f = "file" c...