Search Results

try:
awk '$1=$1' OFS="\n" infile | awk 'l ~ /D 8888 4[34] ./ {sub(".*D 8888 4", "D 8888 4", l) ;print l; l="";} {l=l $1 " ";}
END {if (l ~ /D 8888 4[34] ./) {sub(".*D 8888 4", "D 8888 4", l) ;print...

Are those <new line>s real or just artefacts due to you NOT using code tags? If artefacts, trygrep -o "D 8888 4[43] [^ ]*" file4
D 8888 43 BBBBBBBBBBBBBB
D 8888 44 AAAAA4FFBBBBBB
D 8888 44...

sed 's/\(.\{16\}\).\{16\}/\1AAAAAAAA/' file

The cat command is not necessary since sed can read a file on its own.
The red part is matching another 16 characters, and when you \1 those 16...

You need to give the search pattern something to replace. With BREs:sed 's/\(.\{8\}\).\{8\}/\1AAAAAAAA/' file
gtwrhtrdAAAAAAAArjytwyejtyjejetjyetgeaEHT
wrehrhw2AAAAAAAAytekutkyukrylryilruilrGEQTH...

That is because $line is used unquoted and thus subject to field splitting by the shell (so only the first field will be part of the sed script in quotes).

Try:
sed "/#KEYWORD/a email =...

Try this:
awk '{for(i=1;i<=NF;i++)if($i~/pattern/)print $(i+1)}' infile

you mean "test" in one column?

awk '{printf("%80s %s\n", $1, $2) } ' inputfilename


This assumes your data sample is correct: there are only two "words" on a line

awk 'NR==FNR||FNR==1{printf $0;next}{printf ",%s",$0}' File2 File1 > File3