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echo "<aaa bbb="xxxx" params="@abc@ @defghi@ @j@"></aaa>
<aaa params="@abc@ @defghi@">value</aaa><aaa params="@klm@ @nopq@ @rstu@"></aaa>
<aaa params="@v@ @wxy@ @z@"></aaa>" |
gawk...

awk '/params/{gsub(" @","\" params=\"",$0);i=1;do{sub("params","param"(i),$0);i++}while(match($0,/params/))}1' infile[ctsgnb@shell ~/sand]$ cat tst
<aaa bbb="xxxx" params="@abc@ @defghi@ @j@"></aaa>...

that is correct - whitespace is removed by the shell.

I suggest removing it via the built-in functionality rather then use sed.

ie:
search_string=${var//\//\\/}

search_string=`echo "$var" | sed 's@/@\\\/@g'`

The @ is not a character part of the regex. It is the boundary symbol Scottn choose to build the substitution for the sed utility.
Usually sed uses `/' with the `s' as in sed 's/old/new/' but when...

$ P=/home/smith/packages/cat/abc/def
$ echo $P | sed "s@\(.*/packages/[^/]*/\).*@\1@"
/home/smith/packages/cat/

Hi RickS,

set without options assigns its arguments to the variables $1, $2, etc.. For instance:
# set a b
# echo $1
a
# echo $2
b

-- signifies the end of options. Anything that comes...

while read line
do
eval set -- "$line"
echo "$4"
done < infile
or:
print4()
{
echo "$4"
}

while read line
do
eval print4 "$line"
done < infile

or (ksh93/bash):
while read...

Using built-in bash parameter expansion:
d='/cat/dog/bird/giraffe/ant'; d=${d#*bird/}; echo ${d%/ant*}
giraffe
See man bash -> 'Parameter Expansion' for more infos

#.*/bird/\([^/][^/]*\)/ant.*#

.*/bird/ - anything followed by '/bird/'
\([^/][^/]*\) - followed a FIRST 'capture' of: anything, but '/' repeated 0 or more times
/and.* -...

many ways to skin that cat:

echo '/cat/dog/bird/giraffe/ant' | sed 's#.*/bird/\([^/][^/]*\)/ant.*#\1#g'

Can anyone post alternative sed command to do the same thing?
Actually replacing this "/^a/!"