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ll subdirectory/*.*a*

sed 's/$/ /g' input

true ... just wrote out of habit :)

try using


echo "testing 1 2 3 " | mail -s "subject" abc.com -- -f abc. (shipraa@amdocs.com)com

From the parent directory u can run


find . -name <script_name> | ksh

probably this may help


DEVENS /oravl01/oracle/shipraa > sed 's/[A-Za-z0-9]*\.[A-Za-z0-9]*\.com//g' sample
This is a test file. This is an email address: . This is another line
This is...

echo "1234567890 abc 1234" | awk -F "[a-zA-Z]*" '{print $1 $2}'

if u have the character in a file then
awk -F "[a-zA-Z]*" '{print $1 $2}' sample.txt
where $1 will be before the pattern and $2...

i think the problem is with spaces

try removing them
for i in 1 2 3 4 5 6 7 8
do
j=`expr $i + 3`;
x=`head -$j temp1|tail -1|cut -f24 -d","`;
y=`head -$j temp1|tail -1|cut -f25 -d","`;...

echo "2.326227180240883E7 / 8.509366417956961E8" |awk -F "/" '{print $1 / $2 }'
0.0273373

you may try something like this
echo "aB12Cd" | tr -dc '[a-zA-Z]'

probably not the best way ...but this may work


say sample is the file which is having input then

rm -rf one.txt output.txt
grep -i user sample >one.txt
for i in `cat one.txt`
do
...