String manipulation

 
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Operating Systems OS X (Apple) String manipulation
# 1  
Old 02-06-2017
String manipulation

i have a string that am looking to extract all characters following 3 consecutiv numbers.
Example my string is J1705PEAN038TDMN, i need to get TDMN

My string can have multiple 3 consecutive numbers, i need what follows last occurance
# 2  
Old 02-06-2017
In what language? Applescript? Shell? awk? perl? Other?
# 3  
Old 02-06-2017
shell please
# 4  
Old 02-06-2017
Code:
$ echo "J1705PEAN038TDMN" | grep -o "[0-9][0-9][0-9][^0-9]*$"

038TDMN

$ VAL=$(echo "J1705PEAN038TDMN" | grep -o "[0-9][0-9][0-9][^0-9]*$")
$ VAL=${VAL:3}
$ echo $VAL

TDMN

$

There's probably more elegant ways depending on what your string actually comes from. You could probably extract it - or several - from a file and whittle it down to TDMN, etc in one step.
This User Gave Thanks to Corona688 For This Post:
# 5  
Old 02-06-2017
am parsing a tab delimited text file, one line at the time, your solution works fine, thank you for your help!
# 6  
Old 02-06-2017
Your solution will be very inefficient doing it this way. Care to show your code so I can build it in rather than calling a pointless external? It's quite possible the entire file can be handled in one awk call, instead of having to call grep over and over and over..
# 7  
Old 02-06-2017
Quote:
Originally Posted by gigagigosu
i have a string that am looking to extract all characters following 3 consecutiv numbers.
Example my string is J1705PEAN038TDMN, i need to get TDMN

My string can have multiple 3 consecutive numbers, i need what follows last occurance
is it always the LAST non-numeric sequence of a string?
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