Login or Register to Ask a Question and Join Our Community


OS X (Apple)

Date to epoch problem

Login to Discuss or Reply to this Discussion in Our Community

 
Thread Tools Search this Thread
Operating Systems OS X (Apple) Date to epoch problem
# 1  
Old 10-03-2011
Date to epoch problem
Hi all,

In terminal when I enter:

Code:
date -j -f date -j -f "%Y/%m/%d %T" "2011/09/30 13:00:00" +"%s"

The output is:
Quote:
1317380400



When I put 2011/09/30 in var A, and I subsequently enter:

Code:
date -j -f date -j -f "%Y/%m/%d %T" "${A} 13:00:00" +"%s"

The output is:
Quote:
1317380400



When I put 13:00:00 in var B, and I subsequently enter:

Code:
date -j -f date -j -f "%Y/%m/%d %T" "2011/09/30 ${B}" +"%s"

The output is:
Quote:
1317380400



HOWEVER, when I put both the date and the time in a variable, like this:

Code:
date -j -f date -j -f "%Y/%m/%d %T" "${A} ${B}" +"%s"

I receive the following error:

Quote:
)arning: Ignoring 1 extraneous characters in date string (



This also happens when I put both the date and the time in one variable.

Does anybody know how I can get around this problem?

Thanks a lot!

Kind regards,

M0s..
# 2  
Old 10-03-2011
Hi.

I don't have this problem.

Code:
$ date -j -f date -j -f "%Y/%m/%d %T" "${A} ${B}" +"%s"
1317380400

$ echo $A $B
2011/09/30 13:00:00

$ system_profiler SPSoftwareDataType
Software:

    System Software Overview:

      System Version: Mac OS X 10.7.1 (11B26)
      Kernel Version: Darwin 11.1.0
      Boot Volume: Lion HD
      Boot Mode: Normal
      Computer Name: Scott's iMac
      User Name: scott (scott)
      Secure Virtual Memory: Enabled
      64-bit Kernel and Extensions: Yes
      Time since boot: 21 days 13:29

# 3  
Old 10-03-2011
That's really strange!

Code:
20:41:23 ~ > system_profiler SPSoftwareDataType
Software:

    System Software Overview:

      System Version: Mac OS X 10.7.1 (11B26)
      Kernel Version: Darwin 11.1.0
      Boot Volume: Macintosh HD
      Boot Mode: Normal
      Computer Name: M0sthated
      User Name: M0sthated (mosthated)
      Secure Virtual Memory: Enabled
      64-bit Kernel and Extensions: Yes
      Time since boot: 2:54

Do you have any suggestions??

Kind regards,

M0s..
Last edited by radoulov; 10-03-2011 at 04:59 PM..
# 4  
Old 10-03-2011
Keine Ahnung, as the Germans would say!

From the message (")arning: Ignoring 1 extraneous characters in date string (") I could only guess that you have a hidden (control) character present.

Is this part of a script? If so, what is the output of:
Code:
cat -v file
od -c file

# 5  
Old 10-03-2011
Thanks for your reply.

It is part of a script. I don't observe anything strange when I do cat -v file.

When I do "od -c file" I get:

Code:
(...)
0003100    .   /   \   :   &   /   6   '   `  \n  \t  \t  \t  \t   E   p
0003120    o   c   h   _   e   v   e   n   t   =   `   d   a   t   e    
0003140    -   j       -   f       d   a   t   e       -   j       -   f
0003160        "   %   Y   /   %   m   /   %   d       %   T   "       "
0003200    $   {   E   p   o   c   h   _   e   v   e   n   t   _   d   a
0003220    t   e   }       $   {   E   p   o   c   h   _   e   v   e   n
0003240    t   _   t   i   m   e   }   "       +   "   %   s   "   `  \n
0003260   \n  \t  \t  \t  \t  \n  \t  \t  \t   i   f       [       "   $
(...)

does this look wrong to you?

Thanks!

M0s..
# 6  
Old 10-03-2011
In your original post, you said "However". Was what happened before the "however" also part of the script, or before (i.e. typed from the command line)?

i.e. there's no compelling reason for a command-line version to work, and the script one not to.

At the same time the "od -c" output looks wrong. Can you "cat" the file, and post it here?
# 7  
Old 10-03-2011
Hi Scott,

I wanted to send you the script, but I can't PM you since I only have three posts. Is there a way to send you the script?

Kind regards,

M0s..
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Convert a date stored in a variable to epoch date

I am not able to pass date stored in a variable as an argument to date command. I get current date value for from_date and to_date #!/usr/bin/ksh set -x for s in server ; do ssh -T $s <<-EOF from_date="12-Jan-2015 12:02:09" to_date="24-Jan-2015 13:02:09" echo \$from_date echo... (7 Replies)
Discussion started by: raj48
7 Replies

2. Shell Programming and Scripting

Epoch time to produce exact date everytime

so i have to perform a certain task at set times. for instance, i need to run a job at 12:30am every night, and other jobs, i only need to have them run on saturdays. how do i manipulate the date command to give me the epoch equivalence of what 12:30am would be every day? im looking for a... (3 Replies)
Discussion started by: SkySmart
3 Replies

3. Shell Programming and Scripting

Convert epoch time to Julian date

Need assistance in converting an epoch time to Julian date To get epoch perl -e 'use Time::Local; print timelocal(1,5,2,12,10,2008), "\n"' (3 Replies)
Discussion started by: ajayram_arya
3 Replies

4. Shell Programming and Scripting

Turning given date to epoch

i can probably script this in bash, but, i was wondering, does anyone know of a simple way to translate a given time to epoch? date -d@"29/Oct/2013:17:53:11" the user would specify the date: 29/Oct/2013:17:53:11 and the script will simply interpret that to epoch: 1348838383 (this is just... (4 Replies)
Discussion started by: SkySmart
4 Replies

5. Programming

Converting a user inputted date to epoch time

Hi all , I need to know how to convert a time stamp entered by the user to be converted to GMT/UTC(epoch time) using mktime() and gmtime() for exapample the input will be put in the form ptm.tm_sec = 0; ptm.tm_min = 59; ptm.tm_hour = 11; ptm.tm_mday = 20;... (2 Replies)
Discussion started by: ada
2 Replies

6. Shell Programming and Scripting

Date conversion from Standard/given format to seconds/epoch

I am trying get time difference of two dates in secs. Initially I want to convert a standard date format to epoch for two dates and then subtract the two epoch dates. Example : date -d "2007-09-01 17:30:40" '+%s' But this gives me below error date: illegal option -- d Usage: date OS: AIX... (6 Replies)
Discussion started by: bpaac
6 Replies

7. Shell Programming and Scripting

Get Formatted Date from Unix Epoch

Could someone please explain how to get a formatted date from the unix epoch (the number of seconds since Jan 1, 1970) For example., If the input is 1297969816, then the output should be 2011-02-17 in YYYY-MM-DD formatted manner. I am using AIX sh shell. Tried date -d and date --date, these... (4 Replies)
Discussion started by: Jesinth Nirmal
4 Replies

8. Shell Programming and Scripting

Need to convert an epoch date to MMDDYYHHmm format

System: HP-UX Kornshell Perl is installed, but not POSIX Hello, I am calculating a future date/time. To do this I take the system date in epoch format and add to it. I now need to take the new epoch date and convert it to MMDDYYHHmm format. Any help with this is greatly appreciated. (4 Replies)
Discussion started by: LetsGoPens
4 Replies

9. Shell Programming and Scripting

Date to epoch problem

Hi all! I have a "simple" problem: I want to convert a date and time string (YYYYMMDDhhmmss) to epoch (unix time) in a shellscript. I want to use the "date/time" string as an input to the script, eg: scriptname.sh 20090918231000 and get the epoch format echoed out. Is there an... (3 Replies)
Discussion started by: condmaster
3 Replies

10. Shell Programming and Scripting

Convert date into epoch in Perl on Solaris

Solaris 10 doesn't seem to like me a lot. I am trying to run a simple script to accept date and return epoch of that date: #!/usr/bin/perl -w use strict; use Time::ParseDate; my($date1)="Mon Mar 27 05:54:08 CDT 2009"; chomp $date1; #Convert to seconds since start of epoch my $time1 =... (3 Replies)
Discussion started by: pavanlimo
3 Replies
Login or Register to Ask a Question