Shell Programming and Scripting

f1 f2 output
1 a a
2 b b
b
3 c c
c
c
4 d d
d
d
d

Sorry if i confused you.

And I typed everything in single line at the prompt for the output, it does work no syntax error.

Try (with awk or nawk in case of problem)

Code:

awk '
NR==FNR {
   arr[FNR] = $1;
   next;
}
{
   print arr[FNR],$0 (arr[FNR]>0 ? OFS $0 : "")
   for (i=2; i<=arr[FNR]; i++)
      print $0;
}
' f1 f2

input file f1:

Code:

1
2
3
4
5
6
0

Input file 2:

Code:

a
b
c
d
e
f
z

Output:

Code:

1 a a
2 b b
b
3 c c
c
c
4 d d
d
d
d
5 e e
e
e
e
e
6 f  f
f
f
f
f
f
0 z

Jean-Pierre.

awk ' NR==FNR { arr[FNR] = $1; next; } { print arr[FNR],$0 (arr[FNR]>0 ? OFS $0 : "") for (i=2;>
awk: syntax error near line 1
awk: illegal statement near line 1
awk: illegal statement near line 1
awk: syntax error near line 1
awk: illegal statement near line 1

tried nawk too:

nawk 'NR==FNR { arr[FNR] = $1; next;} { print arr[FNR],$0 (arr[FNR]>0 ? OFS $0 : "") for (i=2; >
nawk: syntax error at source line 1
context is
NR==FNR { arr[FNR] = $1; next;} { print arr[FNR],$0 (arr[FNR]>0 ? OFS $0 : "") >>> for <<< (i=2; i<=arr[FNR]; i++) print $0; }
nawk: illegal statement at source line 1

something is wrong, will try to figure out. Thanks!

When you write the awk program on a single line, don't forget the ";" between statements.

Code:

[n]awk 'NR==FNR { arr[FNR] = $1; next;} { print arr[FNR],$0 (arr[FNR]>0 ? OFS $0 : ""); for (i=2; i<=arr[FNR]; i++) print $0;} ' f1 f2

Jean-Pierre.

no luck...still syntax error

Show us the error message.
Have you tried with awk and nawk ?

Jean-Pierre.

yes it works now with nawk. I had a missing semicolon again.

Thanks.

awk ' NR==FNR { arr[FNR] = $1; next; } { print arr[FNR],$0 (arr[FNR]>0 ? OFS $0 : ""); for (i=2; i<=arr[FNR]; i++) print $0; } ' f1 f2
awk: syntax error near line 1
awk: illegal statement near line 1

was getting this with awk.