Shell Programming and Scripting

We'd need to see the actual code, actual input data, and actual expected result to tell if your code actually does what you think it does.

sorry for being late .. i just logged in the machine:

When the case was to check a specific record

Code:

ASX201123000000010000000202011282004130001001111114320000000200000000000000000010000002300000000100000000101001143211079191

(ONLY when 0000020 and 001 or 002, we change the 0000020 to 0000000)

The actual code was :

Code:

#!/usr/bin/sh
orgv=ASX................0000020.\{77\}00[12]
orgc=0
toproc="/REV/TO_PROCESS"
lgfile="/REV/scripts/rev.log"
for revfile3 in $toproc/REV*
do
      orgc=`grep -E "$orgv" $revfile3 |wc -l`
      if [ $orgc -ge 1 ]
      then
         sed  '/^ASX................0000020.\{77\}00[12]/s/./0/25' $revfile3 > $toproc/temp
         mv $toproc/temp $revfile3
        echo File $revfile3 has some values that have been changed >> $lgfile
    fi
    orgc=0
done

The above code is tested and works fine


NOW the case to check the records has changed..(when the 7 red digits has number in it and there is 001 or 002, change the 7 red digits to zeros)

radoulov and ygemici, kindly, gave me the sed command for the new case:

Code:

sed 's/^\(ASX.\{16\}\).\{7\}\(.\{77\}00[12].*\)/\10000000\2/' infile

which works fine,

also radoulov gave me code to test the records before using the sed command

which works great

Now and out of curiosity, i want the pattern to assign it to orgv variable as i did before. what i mean is something like this:

Code:

orgv=ASX................(any number in the 7 digits).\{77\}00[12]

CAN I echo the lines numbers affected by the sed... if the sed changed lines 5,6,8 in a file, can i show these lines numbers in the log?
thank you

You can. This grep/cut pipeline will give you the affected line numbers:

Code:

egrep -vn '^ASX.{16}0{7}' infile | cut -d: -f1

Note that egrep is not standard (grep -E is).