shell script takes long time to complete


 
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# 8  
Old 02-05-2007
What does the input file format look like?
# 9  
Old 02-05-2007
input file format

The input file format will look like this:

00|AA|BB|CC|DD|
01|EE|FF|GG|
02|HH|KK|LL|
00|AA|BB|CC|DD|
01|...
02|...

And all I need to do is to validate if the number of fields for each line matches the expected number. So there won't any output. just True / False
# 10  
Old 02-05-2007
Forgot to mention that all the fields in each line separated by "|".
# 11  
Old 02-05-2007
Code:
function validate_file
{
    ERROR=0
    OIFS="$IFS"
    IFS="|"
    while read LINE
    do
        set -- $LINE
        LINE_HEAD="$1"
        shift
        case $LINE_HEAD in
            ${FIRST_LEVEL_COUNT}|${SECOND_LEVEL_COUNT})
                if [ $# -ne $LINE_HEAD ]
                then
                    ERROR=1
                    break 2
                fi
                ;;
            *)
                ERROR=1
                break 2
                ;;
        esac
    done < $1
    IFS="$IFS"
    if [ $ERROR -ne 0 ]
    then
        return 7
    fi
}

validate_file $FILE

# 12  
Old 02-05-2007
reborg,

thanks for the reply. But it's a bit hard for me to follow the code. Is it possible to give me a brief explaination?

thanks
# 13  
Old 02-05-2007
Another approach is to do it all in awk, e.g...
Code:
awk -F\| '($1=="00" && NF!=5) || ($1=="01" && NF!=4) {exit 7}' file1

Which could be read as:
IF the first field is equal to "00" and the number of fields is not equal to 5
OR the first field is equal to "01" and the number of fields is not equal to 4
THEN stop scanning the file and exit with error level 7.
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