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Problem with arrays

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# 1  
Old 10-20-2010
Problem with arrays
Hi

I have two arrays:

arr1 = (demo demo2 demo3 demo4 demo5)
arr2 = (demo2 test demo)

I want to check that the values the "arr2" are present in "arr1"

Example

arr1 = (demo demo2 demo3 demo4 demo5)
arr2 = (demo2 test demo)

Output: Error

arr1 = (demo demo2 demo3 demo4 demo5)
arr2 = (demo2 demo5)

Output: OK

Thanks for your help SmilieSmilieSmilieSmilie
# 2  
Old 10-20-2010
What shell are you using? What have you tried?
# 3  
Old 10-20-2010
Quote:
Originally Posted by Corona688
What shell are you using? What have you tried?
I using bash.

Code:
#!/bin/bash

arr1="demo demo2 demo3 demo4 demo5"
arr2=$(echo 'demo2,test,demo' | sed 's/\.*,/ /g')

for i in $arr2
do
   list="$list $i.out"
done

echo $list

The second array is assembled from a list of parameters passed, I have the arrays ok, but do not know how to verify that the values the "arr2" are present in "arr1" as I said in the beginning of the post.

Thank
# 4  
Old 10-20-2010
Those aren't arrays at all, for starters.

Code:
arr1=( demo demo2 demo3 demo4 demo5 )
OLDIFS="${IFS}"
# Special variable that controls how shell splitting works
IFS=","
VAR="demo2,test,demo"
# Will split apart on IFS
arr2=($VAR)
# Change it back since important things can break if we don't
IFS="${OLDIFS}"

for ((N=0; N<${#arr1[@]}; N++))
do
        echo "arr1[$N] = ${arr1[$N]}"
done

Another loop inside, on arr2, will let you check every element against every other element.
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