grep a pattern with line numbers.

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Grep for a line containing only 5 numbers

How would you grep for a line containing only 5 numbers? Something like this. 10 2 12 1 13

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sed pattern fails to delete line of numbers

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sed command to grep multiple pattern present in single line and delete that line

here is what i want to achieve.. i have a file with below contents cat fileName blah blah blah . .DROP this REJECT that . --sport 7800 -j REJECT --reject-with icmp-port-unreachable --dport 7800 -j REJECT --reject-with icmp-port-unreachable . . . more blah blah blah --dport 3306...

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Grep lines with numbers greater than 2 digits at the end of the line

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Grep the word from pattern line and update in subsequent lines till next pattern line reached

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Get line numbers while searching the pattern in log

Hi Folks, I am searching for a pattern in logs through putty by opening the file in vi editor and reaching to the last of the file by $ and then searching the pattern , lets say I have to search the pattern abc then it would be ?abc Now I want line numbers along with the matching pattern to be...

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grep to get line numbers

I know if i use grep -n that the output will have the lines numbered but is there a way to grep the actually line number. so like this grep -n "one" /usr/dict/numbers 1:one 21:twenty-one 31:thirty-one 41:forty-one 51:fifty-one 61:sixty-one 71:seventy-one 81:eighty-one 91:ninety-one ...

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