Shell Programming and Scripting

Hi, Can somebody help me to know how to invert the positions of this construct?
${variable%pattern} to ${pattern%variable} for pattern matching positions.

Example 1

Code:

var=testcase
echo {var%e}
testcas

So I am not sure how to invert variable and pattern so I can do something like this
Example 2

Code:

var=testcase
echo {e%var}
testcas

I appreciate any help, thank you.

1. Why do you want to do that?
2. What do you mean with "invert" ?
3. You cannot change the parameter expansion syntax

1. I am working on a small project in my job where we need to run a database for a small program in redhat but we need the home directory of every user, so since we don't want to make the changes manually for so many of them, better do it this way with a small script program.
2. Well, let me give you a simple example of this.
./program /home/user /home
the output would be: user
so I was thinking that may be I could switch it and the input would be like this: ./program /home /home/user and output would be: user.
3. I didn't explain my self very well, thank you.

So if we take /program /home/user /home as an example, the first parameter to the script is /home/user, so that would become variable $1 inside the script. You could use:

Code:

user=${1##*/}

You can read more about this here: Shell Command Language: Parameter Expansion

Thank you Mr. Scrutinizer.

Let me put what I was looking for and the nice solution.
THIS IS THE COMMON WAY.
# rightmatch value pattern

echo -e ${1%$2}
echo
rightmatch value pattern
./rightmatch /home/user /*
/home
--------------------------------------------------
THE WAY THAT I WAS LOOKING FOR WAS THIS
pattern=$1
value=$2

echo -e ${value#$pattern}
echo
$ leftmatch pattern value
./leftmatch /* /home/user
/home

So thank you for your help.