UNIX for Dummies Questions & Answers

i'm trying to write a script that will check my os x box for uptime and autorestart gracefully if the uptime is greater than a certain number of days.

thus far i have this:

if uptime | cut -d ',' -f 1 | cut -d ' ' -f 4 -gt 10 ; then
echo "yes"
fi

this doesn't work and i've tried brackets, parenthesis, etc to get it to work. can someone direct me to the correct syntax please?
thanks!

try this ....

uptime | cut -d "," -f 1 | tr -s " " | cut -d " " -f 4

Complete script ....

if test `uptime | cut -d "," -f 1 | tr -s " " | cut -d " " -f 4` -gt 10 ; then
echo "yes"
fi

sorry but it doesn't work as expected. cut returns "days"

removing the middle part to return the value i'm looking for still doesn't work either:

if test `uptime | cut -d "," -f 1 | cut -d " " -f 4` -gt 10 ; then
echo "yes"
fi

it doesn't return "yes". i'm using bash.
thanks

What unix u have ...
for AIX ... See the following working for me ...
$ uptime | cut -d "," -f 1 | tr -s " " | cut -d " " -f 4
23

Can u try ... putting 3 instead 4 for the last cut

try the following and let me know ....
uptime | cut -d "," -f 1 | tr -s " " | cut -d " " -f 3

using apple OS X... the uptime line works by itself in the terminal. when i add it to the if-then script and call the script from the terminal it doesn't work. i'm guessing it has something to do with the quotes or possibly bracketing it right.

1)which quote are u using ? Is it the one below ESC key on the key-board.
You have to use that quote only.

2) If that does n't work ....
put that whole command to variable and include that variable
for ' if ' syntax.

var = `uptime | cut -d "," -f 1 | tr -s " " | cut -d " " -f 4`
if test $var -gt 10
then
echo "Yes"
fi

3) Check 'if' syntax as per apple OS.