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extracting return of ls -l into variables

 
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# 1  
Old 03-01-2006
extracting return of ls -l into variables
If I do "ls -l filename" in a script, it should return something like this:

-rw-r--r-- 1 user group 5945 Feb 28 14:24 filename

How do I put each of the above strings into a different variable?

eg Permissions, username, groupname, date
# 2  
Old 03-01-2006
something like this,

Code:
ls -l filename | awk '{print $1, $3, $4, $6"-"$7"-"$8}' | read perm username grpname date

# 3  
Old 03-01-2006
Excellent. Thanks a lot!
# 4  
Old 03-01-2006
Okay, I've been playing around with the command you gave me, matrixmadhan, but I can't figure out how to print the fields $1, $2, $3 etc to different variables. They always either end up in the first variable, or all the variables remain blank. Any ideas?
# 5  
Old 03-01-2006
That command will only work if your shell is ksh.
# 6  
Old 03-01-2006
Right. I'm in a bash shell. Any ideas about how I go about it in that?
# 7  
Old 03-02-2006
You can set named variables like $perm $username etc by using something like this....
Code:
eval $(ls -l file1|awk '{printf "perm=%s username=%s", $1, $3}')

...but you can just use set to set $1 $2 etc, e.g...
Code:
set -- $(ls -l file1)
perm=$1
username=$3

Last edited by Ygor; 03-02-2006 at 01:29 AM..
 
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