Shell Programming and Scripting

Hi friends,

I have on data file containing 3 coloums...........

like this.


**** ***** *****
*** ***** *****
*** ***** *****
12.36 13,27 22.16
**** ***** *****
**** ***** *****
**** ***** *****
**** ***** *****
12.35 32.46 34.56

now from the above file i want to write only where the 3 fields are not blank.

can i use awk command.......
plz give me sysntax/........

Do you mean to say the lines are empty..Then just delete the lines

Code:

sed '/^[ \t]*$/d' inputfile

or

Code:

sed '/^$/d' inputfile

the above command not working.....
do u know awk syntax.............
i want only which row has the data based on third coloum..

Code:

awk 'NF==3' inputfile

thank u for reply.................
it not working......

actually my question is display the lines where field 3 is not blank.

so the output should like this....

23.12 78.34 22.1
17.68 65.34 24.5
21.78 70.87 26.8

please verify and let me know............


thank u
rajan

Try...

Code:

awk '$3+0!=0' file1

Or...

Code:

awk '$3!~/^*+$/' file1

So you don't want the "***" fields? only everything else? yes/no?
ie
grep -v "^*" filename
23.12 78.34 22.1
17.68 65.34 24.5
21.78 70.87 26.8