Shell Programming and Scripting

Hi

I need help i Loop format

If i use the Following syntax

$ for i in `echo "Hello world"`
do
echo $i
done

Output is:
Hello
world

But i need Output in One line "Hello world"

Can any one help?

If i use while loop it works?
I want to use for loop only.

Thanks in advance

Here is what you want, but why do an echo of that? AN echo "hello world" would give you what you request

for i in "echo hello world"
do
echo $i
done

Hi
Thanks for your prompt response.

Here is my question:

In My script at some place I'm reading one file in for loop:

cat file_name
abc|xyz|Hello World|

for i in `cat file_name`
do
x=echo $i|cut -f1 d'|'
y=echo $i|cut -f2 d'|'
z=echo $i|cut -f3 d'|'

command1
perform action

command2
perform action

done

The above for loop result is splitting into 2

abc|xyz|Hello
World

I want to read "Hello World" as one argument

please help

Thanks

have a try with awk instead of cut, it should be ok after.
This sounds like school work, be aware that it's not excepted here..


Cheers


Jason

for i in `echo "Hello world"`
do
echo "$i \c"
done

Code:

#!/bin/ksh

while IFS='|' read command1 command2 command3 junk
do
   echo "[$command1]"
   echo "[$command2]"
   echo "[$command3]"
done < file_name

Thanks for your response and support.
I managed to solve the problem.


Converting spaces into strings and putting it back. coz "for loop" can't read as continuous line if there is space in between (as i know)

cat file_name
abc|xyz|Hello World|
xas|ewe| Simple QA|
(Here i know space is only for 3rd argument)

for i in ``awk '{gsub(" ",",");print}' file_name`
do
x=echo $i|cut -f1 d'|'
y=echo $i|cut -f2 d'|'
z=echo $i|cut -f3 d'|' | awk '{gsub(","," ");print}'`

command1
perform action

command2
perform action

done