Shell Programming and Scripting

I have some txt files. I have to create another text file which contains the portion starting from the format "Date Sex Address" to the end of the file. While using grep -n on Date it also gives me the previous line containg Date. and also Date may be DATE in some files.
My file is like this
Name:
Mod Date
Mod By
Description
Date Sex Address
...
....
...

I want my new file to contain from "Date sex " to the end of file. thanks in advance.

Something like this should do it:

Code:

awk '/^Date Sex Address/{f=1;next}f' file > newfile

Regards

Hi,
I need the line number which contains these three words if contain in the same line.

Like this?

Code:

awk '/^Date Sex Address/ || /^DATE Sex Address/ {print NR}' infile

Assuming that the pattern is "Date Sex Address" and not any combination thereof

Code:

$ sed -n '/Date Sex Address/=' file
5

I want the line number from the file which contains all the 3 words using any unix command or utility. i am intrested in getting the line number

Code:

grep -n 'Date Sex Address' file

Regards