Shell Programming and Scripting

Hi everyone


I want to know how can we pass multiple argument in getopts

suppose

Code:

 
PARAMS="abcd"
 
while getopts ${PARMS} FLAG
 do
    case ${FLAG} in
(a) 
(b)
(c)
(d)
      esac

now if i want to define another parameter as st


then how would i define in PARAMS above.

please help

From man bash:
One character per option. If you need something different, you will have to parse the parameters in a different way. On the other hand, there are plenty of characters left in the alphabet, so why not just take s?

hii

thanks for reply

actually my requirement is that only that i need to pass

st as argument on command line prompt

so can u please tell me how to do it

Just leave getopts out and use case and test $1. Check any basic shell scripting guide on the www for positional parameters.

Hi

thanks for reply

but this means we cannnot acheive this via getopts actually if i change it from getopts functionality to case functionality it would not be feasible in my program

i have to achieve it through getopts functionality

can't we have multiple character argument in getopts

Why not? Why?

because my code is having all parameters processed through getopts so i think according to requirement i should processed the new parameter with getopts only to not to change the functionality.

i tried implementing through case but it is giving me error i explain u how

initally my code is

PARAMS="abcd"

Code:

while getopts ${PARMS} FLAG
do
    case ${FLAG} in
(a) 
(b)
(c)
(d)
      esac

and suppose i invoke this code as

Code:

./abc.sh -a -b -c -d

but now suppose after this four parameter i introduced a new parameter -st then the code would be

PARAMS="abcd"

Code:

 
while getopts ${PARMS} FLAG
do
    case ${FLAG} in
(a) 
(b)
(c)
(d)
      esac
if [[ $5 == "-st" ]]
then
echo "any"
fi

if i invoke this code now as

Code:

./abc.sh -a -b -c -d -st

then it gives me error

Code:

ERROR is getopts bad option -s