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How to get the ceiling value for floating numbers?

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Top Forums Shell Programming and Scripting How to get the ceiling value for floating numbers?
# 1  
Old 10-29-2009
How to get the ceiling value for floating numbers?
Dear guys;

How can I get the ceiling value of any floating number using shell or awk scripts or functions.

Code:
Example:-

old values "7.2" or "7.8" or "7.5" --->>> ceiling  function ---->>> new value "8".

BR
Last edited by ahmad.diab; 10-29-2009 at 08:39 AM..
# 2  
Old 10-29-2009
Code:
echo "7.2" | awk '
   function ceil(valor)
   {
      return (valor == int(valor)) ? valor : int(valor)+1
   }
{
   printf "%d", ceil($1)
} '

Last edited by pludi; 10-29-2009 at 05:40 AM.. Reason: code tags, please...
# 3  
Old 10-29-2009
Thanks man :-)
# 4  
Old 10-29-2009
The solution above doesn't give the correct result for negative numbers:

Code:
$ echo "-3.1" | awk '
   function ceil(valor)
   {
      return (valor == int(valor)) ? valor : int(valor)+1
   }
{
   printf "%d", ceil($1)
} '
-2

Try this instead:

Code:
awk '{printf("%d\n",$0+=$0<0?0:0.9)}'

Examples:

Code:
$ echo "3.1" | awk '{printf("%d\n",$0+=$0<0?0:0.9)}'
4
$ echo "3.0" | awk '{printf("%d\n",$0+=$0<0?0:0.9)}'
3
$ echo "0.1" | awk '{printf("%d\n",$0+=$0<0?0:0.9)}'
1
$ echo "-3.1" | awk '{printf("%d\n",$0+=$0<0?0:0.9)}'
-3
$ echo "-3.9" | awk '{printf("%d\n",$0+=$0<0?0:0.9)}' 
-3

Regards
# 5  
Old 10-29-2009
Thanks Franklin I have missed your mention point about negative numbers...thanks a lot man.

BR
# 6  
Old 10-29-2009
Quote:
Originally Posted by Franklin52
Code:
awk '{printf("%d\n",$0+=$0<0?0:0.9)}'

[/CODE]
Will only work with one decimal:

Code:
$ cat infile
7
7.0
7.05
7.5
7.505
7.6
0
-7
-7.0
-7.05
-7.5
-7.505
-7.6

Code:
$ awk '{printf("%s \t  %d\n",$0, $0+=$0<0?0:0.9)}' infile
7 	  7
7.0 	  7
7.09 	  7
7.5 	  8
7.505 	  8
7.6 	  8
0 	  0
-7 	  -7
-7.0 	  -7
-7.09 	  -7
-7.5 	  -7
-7.505 	  -7
-7.6 	  -7

Workaround:
Code:
$ awk '!$0{print;next}{printf "%s\t%d\n",$0,($0%int($0))?int($0)+(($0>0)?1:0):$0}' infile
7	7
7.0	7
7.09	8
7.5	8
7.505	8
7.6	8
0
-7	-7
-7.0	-7
-7.09	-7
-7.5	-7
-7.505	-7
-7.6	-7

But that's becoming a bit bloated for a simple round-up IMO.
# 7  
Old 10-29-2009
Quote:
Originally Posted by ripat
Will only work with one decimal:
A slightly modification like this should be sufficient:

Code:
awk '{printf("%d\n",$0+=$0<0?0:0.999)}'

Regards
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