Shell Programming and Scripting

Hi,

I have a .ksh script, and I read files from a directory with "set" command:

Code:

set B*.txt

Means I can now assign with

Code:

file1=$1

the first filename found to a variable file1.

How can I count how many files it has found with "set"?

Thanks,
Michael

Code:

echo $#

Thanks!

Do you maybe also now how to manage, that the filenames are assigned to a variable in a loop, like:

Code:

set B*.txt
i=1
c=$#
x=$((c+1))
echo "$x"

while [[ $x -gt i ]] ; do
_ftpfile$i="$"$i
echo "$_ftpfile$i"
i=$((i+1))
done

the first echo returns, that x = 4, and as long x is not gt. than i(=1), it should create a variable _ftpfile$i (_ftpfile1, _ftpfile2, _ftpfile3) with the value of the set command, means the filename in $i (which should be $1, $2 and $3).

here's the output:

4
awkb.ksh[13]: _ftpfile1=$1: not found
1
awkb.ksh[13]: _ftpfile2=$2: not found
2
awkb.ksh[13]: _ftpfile3=$3: not found
3

---------- Post updated at 05:01 PM ---------- Previous update was at 04:44 PM ----------

ok maybe thats a new question for all ... so thanks so far for help on that one ...

Code:

eval _ftpfile$i="$"$i

do you maybe also know how to chmod the files?

Code:

chmod 744 file

Check chmod in manual for more options

I think it does not work that way within the same loop when creating the variables in the ksh?