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Grep AND

 
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# 1  
Old 04-09-2010
Grep AND
Hello all,

I have many files in a directory and I'm trying to read each file in the directory, search for four patterns and return the name of the file only if it contains each of the 4 patterns. I'm familiar with using egrep -l "(pattern1|pattern2)" *, but it seems like doing something similar by using an AND isn't so easy. Does anyone have a good idea on how to accomplish this?

So for example:
Dir: /home
file1
file2
file3
file4
filexx

Contents of each file:
config router id x.x.x.x
interface passive x.x.x.x
x.x.x.x 255.255.255.255 area

pattern1 = config router id x.x.x.x
pattern2 = interface passive x.x.x.x
pattern3 = x.x.x.x 255.255.255.255 area

I want to grep each file in the home dir for (pattern1 & pattern2 & pattern3) and return the name of the file with the info.

I hope this makes sense.
# 2  
Old 04-09-2010
Give a more precise example of the patterns and the desired output.
And please use code tags.
# 3  
Old 04-09-2010
I gave the patterns I would like to search for:

pattern1 = "config router id x.x.x.x"
pattern2 = "interface passive x.x.x.x"
pattern3 = "x.x.x.x 255.255.255.255 area"

The desired output is:
filename1
filename2

...maybe file3 or filename3 doesn't contain each of the three specified patterns so it wasn't returned in my example. I didn't use code tags because I haven't provided any code. Everything has been pseudo so far.
# 4  
Old 04-09-2010
grep can't do logical operations between multiple different patterns. You'll either need to run grep four times, or write a script to do the matching more efficiently. Does your system have BASH?

Code:
#!/bin/bash
STRINGS=( "config router id x.x.x.x"
                "interface passive x.x.x.x"
                "x.x.x.x 255.255.255.255 area" )

while [ ! -z "$1" ]
do
        MATCH=()


        while IFS="" read LINE
        do
                for ((N=0; N<${#STRINGS[@]}; N++))
                do
                        [ -z "${MATCH[$N]}" ] || continue
                        [[ "$LINE" =~ ${STRINGS[$N]} ]] && MATCH[$N]=1
                done
        done < "$1"

        TOTAL=0
        for ((N=0; N<${#STRINGS[@]}; N++))
        do
                [ -z "${MATCH[$N]}" ] || TOTAL=$((TOTAL+1))
        done

        [ "$TOTAL" -eq "${#STRINGS[@]}" ] && echo "$1"
        shift
done

You can run this like ./script file1 file2 file3 file4 and it'll print the names of the files that match all the patterns listed in STRINGS. Note these patterns are full-out regular expressions. May not be the fastest horse in the west but probably faster than running grep four separate times.
# 5  
Old 04-09-2010
An approach with awk:
Code:
awk '
!f{f=FILENAME}
$0 ~ p1 {a++}
$0 ~ p2 {b++}
$0 ~ p3 {c++}
FILENAME != f {
  if( a && b && c ) {print f}
  f=FILENAME
  a=b=c=0
}
END{if( a && b && c ) {print f}}
' p1="config router id x.x.x.x" p2="interface passive x.x.x.x" p3="x.x.x.x 255.255.255.255 area" file*

Last edited by Franklin52; 04-10-2010 at 09:48 AM.. Reason: adding END block
 
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