Shell Programming and Scripting

Hi ,i want to convert the timestamp of file into yyyymmdd hh:mi:ss format.I tried ls -l test |awk -F" " '{print $6,$7,$8}' and the result I got was Jul 16 21:31.Can some one help me how do i get his into yyyymmdd hh:mi:ss format.Thank you

If your on a modern unix (with GNU data and stat command)

you could try:

Code:

$ date -d @$(stat -c %Y test) '+%Y%m%d %H:%M:%S'
20120716 21:31:12

Hi ,I am on AIX unix and i do not have date -d functionality.How ever I can access istat command ,but it gives the result as

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Last updated: Wed Jul 4 05:06:03 2012
Last modified: Fri Feb 24 23:21:05 2012
Last accessed: Fri Jun 29 18:14:57 2012
I did grep and awk,but I am getting as Fri Feb 24 23:21:05 2012.How do I get in the time stamp format yyyymmdd hh:mi:ss

How about this

Code:

$ istat test | awk '
BEGIN{
  split("Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec",n,",")
  for(mth in n) m[n[mth]]=mth
}
/Last modified/ { printf "%04d%02d%02d %s",$8,m[$4],$5,$6 }'
20120224 23:21:05