sttime(3) ShapeTools Toolkit Library sttime(3)NAME
stMktime, stWriteTime - date and time handling
SYNOPSIS
#include <config.h>
#include <sttk.h.h>
time_tstMktime (char *string);
char*stWriteTime (time_t date);
DESCRIPTION
stMktime scans the given string and tries to read a date and time from it. It understands various formats of date strings. The following is
a list of all valid formats, optional parts in brackets.
[Tue] Jan 5[,] [19]93
This includes the standard asctime(3) format.
Jan 5 With no year given, the year defaults to the current year.
[19]93/01/05 This notation requires month and day represented by exactly two digits.
5.1.[19]93 This is the usual German notation.
5.1. German notation referencing the current year.
A certain time, given together with the date must always have the following form.
hours:minutes[:seconds]
Each of the fields must be an integer value within the proper range (hours: 0-23, minutes and seconds: 0-59). Values below
10 may be written as one digit numbers.
The time value may be placed anywhere in the date string: at the beginning, at the end, or somewhere in the middle. Any amount of white-
space may be given between a field of the time value and the separating colon. The time is always considered to be local time.
stWriteTime generates a time string similar to asctime(3) from its date argument.
SEE ALSO asctime(3)BUGS
Time Zone Names within the time string (like `MET') are not handled properly. In most cases they will cause a failure.
sttk-1.7 Thu Jun 24 17:43:35 1993 sttime(3)
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sttime(3) ShapeTools Toolkit Library sttime(3)NAME
stMktime, stWriteTime - date and time handling
SYNOPSIS
#include <config.h>
#include <sttk.h.h>
time_tstMktime (char *string);
char*stWriteTime (time_t date);
DESCRIPTION
stMktime scans the given string and tries to read a date and time from it. It understands various formats of date strings. The following is
a list of all valid formats, optional parts in brackets.
[Tue] Jan 5[,] [19]93
This includes the standard asctime(3) format.
Jan 5 With no year given, the year defaults to the current year.
[19]93/01/05 This notation requires month and day represented by exactly two digits.
5.1.[19]93 This is the usual German notation.
5.1. German notation referencing the current year.
A certain time, given together with the date must always have the following form.
hours:minutes[:seconds]
Each of the fields must be an integer value within the proper range (hours: 0-23, minutes and seconds: 0-59). Values below
10 may be written as one digit numbers.
The time value may be placed anywhere in the date string: at the beginning, at the end, or somewhere in the middle. Any amount of white-
space may be given between a field of the time value and the separating colon. The time is always considered to be local time.
stWriteTime generates a time string similar to asctime(3) from its date argument.
SEE ALSO asctime(3)BUGS
Time Zone Names within the time string (like `MET') are not handled properly. In most cases they will cause a failure.
sttk-1.7 Thu Jun 24 17:43:35 1993 sttime(3)
How can I do this:
date = 4 -----------> 04
Month= 3-----------> 03
I wish to make a varibale named Var1 which will hold the value of current date and month value as:
2 digits for date.
2 digits for month.
So finally var1 should hold value as 0403 --- MMDD (11 Replies)
Hi All,
I like to read the log file from specific time to end of the file.
eg:
message
date and time
message 1
date and time1
message 2
EOF
I want to read all the text (Messages) after date and time to end of the file.
Please let me know the UNIX command to perform this?.
Thanks,... (9 Replies)
Hi All,
My requisite is to search for the string "0108"(which is the year and has come in the wrong year format) in a particular column say 4th column in a tab delimited file and then replace it with 2008(the correct year format) in the same position where 0108 was found..The issue is the last... (15 Replies)
Hi All,
My requisite is to search for the string "0108"(which is the year and has come in the wrong year format) in a particular column say 4th column in a tab delimited file and then replace it with 2008(the correct year format) in the same position where 0108 was found in the same file..The... (27 Replies)
Hi All, I'm new to this forum, and appreciate any assistance with my issue.
I have a shell script that logs into an oracle DB and runs a sqlplus query. Everything works great except for the time I get. I'm new to shell so bare with me. What would be the code and where do I place it?
My... (18 Replies)
i have the time 20100421043335 in format (date +%Y%m%d%H%M%S),and i want to be able to get the previous time 2 minutes ago,which is
20100421043135 (9 Replies)
Scripting Guru's,
I need your help, can you tell me how i can check a file from a certain point onwards via a ksh script.
Currerntly i am checking the whole file and can't script it so it checks from 17.01.2012 20:00:00 onwards please..
Any help will be greatly appericated.
See file... (10 Replies)
I have a filename like 1_DATE_3_4.5_888 and I want to modify the date field (ie the last 4 digits ) alone and remove the last field.
Old filename:1_DATE_3_4.5_888
Given date (for eg):120606259532
modified date:120606259899
new filename:1_<modified date>_3.4.5 (14 Replies)
Hi,
I'm trying to get the name of a file that has the current date in the name.
The filename is on the form A<current date>01.DC, for example A2012110501.DC
I have this script so far
date +%y%m%d
D=$(date +%y%m%d)
N=A20$D
echo $N
N2={$N}01.DC
echo $N2
And gets the following... (12 Replies)
Why is the result of this command off (or less) by one hour
date --date "1979-10-26 +54 hours" +%Y%m%d%H
The result is
1979102805
It actually should be
1979102806
It does it with adding minutes as well and only occurs on Oct. 26, from what I can tell. What's going on here? (9 Replies)
Dear community,
i got a problem to get "date +%j" as the right value.
Today is the 10th day of the year.
#./script.sh 2
#!/bin/bash/
Var1=$(date +%j)
Var2=$1
let result=$Var1+$Var2
echo $Var1 plus $Var2 equals $result
The output of the script is:
010 plus 2 equals 10... (9 Replies)
Hi,
I need to subtract 5 minutes from the date. Example
$date +"%Y-%m-%d-%H.%M.%S" displays 2014-06-26-06.06.38
I want to show it as 2014-06-26-06.01.38 (5 mins are subtracted from date)
Any help would be appreciated. I am currently on AIX version 6.1
-Vrushank (10 Replies)
Hello,
How can we convert date like format 20181004171050 in seconds ?
I can able to convert till date but failing for HHMMSS.
date -d "20181004" "+%s" output as 1538596800 .
But when i add hhmmss it is failing date -d "20181004172000" "+%s" result Invalid date
Kindly guide.
Regards (16 Replies)