Linux

Hi,

Can you please help me of how to store the values into variables.

Here is the output in LINUX for the below command.

$free

output :
total used free
Mem: 3079276 3059328 19948
Swap: 1023992 6324 1017668

while i am trying the below commands i got the ouput
free |grep "Mem:" |awk ' {print $2}'
output for the above cmd is printing == 3079276

similar to the swap as well..

But i want to store the ouput value in a variable

I also decalred the variable like this

$Memory=`free |grep "Mem:" |awk ' {print $2}'`;
print "$Memory ";
It is printing like this
Mem: 3079276 3059328 19948

Can anyone please help me regarding this how to store the values into variables....

Try this:

Code:

Memory=$(free | awk '/Mem:/{print $2}')
print $Memory

Regards

$2 in the awk script probably gets substituted with something unexpected when you evaluate it in backticks in Perl. $2 in Perl is the result of the second set of parentheses in the latest regular expression match; presumably it's empty, so the awk script is just "print".

Quote the variable properly, and it should work.

Note, though, that you have a Useless Use of Grep when you pipe to awk -- awk can grep just fine. And by the same logic, I guess it's a Useless Use of Awk to call awk from Perl, because Perl can do everything awk can, only better.

Code:

perl -e '$mem = `free`; $mem =~ s/.*Mem:\s+(\d+)\s.*/$1/s'

The /s option causes .* to match across newlines, so you can handle the multiple lines of output from free as one expression.

It is working fine now. I appreciate your help.Once again thanks a million.