And you are on Linux? What version of date do you have (does it grok "date --version")?
Check your PATH, you might have some weird ancient BSD relic date in your PATH overshadowing the real McCoy ...? (Does "type -all date" reveal any shadows?)
And you are on Linux? What version of date do you have (does it grok "date --version")?
Check your PATH, you might have some weird ancient BSD relic date in your PATH overshadowing the real McCoy ...? (Does "type -all date" reveal any shadows?)
If you have Perl, the Perl FAQ has a nice answer.
my bad I'm actually on a solaris box
typing date --version threw:
date: illegal option -- -
date: illegal option -- v
date: illegal option -- e
date: illegal option -- r
date: illegal option -- s
date: illegal option -- i
date: illegal option -- o
date: illegal option -- n
usage: date [-u] mmddHHMM[[cc]yy][.SS]
date [-u] [+format]
date -a [-]sss[.fff]
i basically want to delete files over 3 days old in a directory using the current date as a marker...i cant use -mtime as a person may modify the file and the modified time will not be the same as the filename. So therefore i am using the filename as the second time stamp. if you follow me?
Hmm. Maybe the coordinates I had were correct.... or not -
here is an updated version
Code:
#!/bin/ksh
sec()
{
perl -e '
use POSIX qw(strftime);
$fmt = "%s"; # %s = seconds in epoch
$mday = substr("$ARGV[0]", 6, 2);
$mon = substr("$ARGV[0]", 4 ,2);
$year = substr("$ARGV[0]", 0 ,4);
$hour = substr("$ARGV[0]", 8 ,2);
$min = substr("$ARGV[0]", 10 ,2);
$sec = substr("$ARGV[0]", 12 ,2);
$secs =
strftime($fmt, $sec, $min, $hour, $mday , $mon - 1, $year - 1900, -1, -1, -1);
print int $secs;
' "$1"
}
echo "today is = `date` `date "+%s"` as a sanity check"
today=$( date "+%Y%m%d%H%M%S" )
today=$( sec $today )
oldat=$( sec "20080313101504" )
ddiff=$(( $today - $oldat ))
echo "$today minus $oldat = $ddiff which is \c"
if [[ $ddiff -lt 259200 ]] ; then
echo "less than three days \c"
else
echo "greater than three days \c"
fi
echo " (259200 seconds)"
output
Code:
csadev:/home/jmcnama> ddiff.pl
today is = Tue Mar 18 09:39:21 CDT 2008 1205851161 as a sanity check
1205851161 minus 1205421304 = 429857 which is greater than three days (259200 seconds)
Last edited by jim mcnamara; 03-18-2008 at 11:39 AM..
Hi,
I created a script for finding the duration of a job using the start and end time of the job. But the command doesnt calculate correct value if the duration is more than 24 hours. Any help would be really good
.
cat test1 --- start time
03/27/15 17:41:00
03/24/15 11:58:04
03/23/15... (3 Replies)
Hi Everyone,
We are having an issue with date and date -u in our AIX Systems.
We have checked environment variable TZ and /etc/environment and however, we could not rectify the difference.
>date
Thu Mar 19 22:31:40 IST 2015
>date -u
Thu Mar 19 17:01:44 GMT 2015
Any clue... (5 Replies)
I tried the below code to find difference between two dates. It works fine if the day of the month is 2-digit number. But it fails when we have a single-digit day of month(ex:1-9). my code is as below. please help me soon.
#!/usr/bin/perl -w
use strict;
use Time::Local;
... (2 Replies)
1. The problem statement, all variables and given/known data:
The problem i have is that i probably make a few mistake here in the code but don't know what it is and i try to get the date difference but don't know where to add the days_in_month function
2. Relevant commands, code,... (1 Reply)
Dear all,
I fancy that I'm pretty competent in ksh, but I have someone on HP-UX wanting me to script up a simple interface to handle user alterations rather than giving them high privileges to run up SAM. This is all fairly straightforward, but I'm stuck on an epoch date issue.
When we have... (6 Replies)
Hi All!
I would like to know the time difference between two dates which are in same format...
$ date -r abc
Thu Oct 29 09:40:37 EDT 2009
$ date
Fri Oct 30 02:07:03 EDT 2009
i would like to find the diff between these two dates in hours..please help..:)
Regards,
Kiran (3 Replies)
if there are two date one is entered by user
and another is system date than how can we finds day difference
between these two date
try to make it within 4 lines (2 Replies)
Hi
Can any buddy give mi a simple program or logic or command which will get
difference between two dates
ex:diff between 20051008 2005908 is 24hours 12 min 2 sec
regards (1 Reply)
Hi...I need some help with a date script. I need to allow the user to enter the month (alpha) day (int) and year (YYYY) and count the difference in number of days since Jan 1, 1952 to the users date. I've been messing with this for about 10 hours and I think I'm just making the script worse =(
... (1 Reply)