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Operating Systems Linux Need help on 2>&1
# 1  
Old 11-28-2011
Need help on 2>&1
I need help. I'm trying to have the out of en error not only show up on the screen , but also be copied into a file.

This is part of my script
Code:
file="`date +%b_%d_%y:%H:%M:%S`"
touch $file | mv $file ~/errors/idtoolerrorlogs | cp ~/errors/idtoolerrorlog ~/errors/idtoolerrorlogs/$file
 
 
~/errors/idtoolerrorlog > ~/errors/idtoolerrorlogs/$file 2>&1

All this does is print the result on the screen. But it does not print in the file. Any thoughts
Last edited by Scott; 11-29-2011 at 09:24 AM.. Reason: Code tags
# 2  
Old 11-28-2011
You can pipe your command to tee so you get output on screen and also on a file.

Code:
<some commands> 2>&1 | tee log.out

# 3  
Old 11-28-2011
With 2>&1 you are redirecting STDERR to STDOUT. From the first look of the script, it seems to be broken. Can you please post the whole script with CODE tag around it? I do not see anything where you are feeding errors to STDERR.

Code:
~/errors/idtoolerrorlog > ~/errors/idtoolerrorlogs/$file 2>&1

The above line should not work as idtoolerrorlog is a text file and you need to use cat command to print its content and then redirect.

Please post the full script to help you better.
# 4  
Old 11-29-2011
The whole script
Code:
#!/bin/bash
 
#Linux Script
 
echo "`date +%D:%H:%M:%S`" ; read -p " User ID"= UserID
 
echo "`date +%D:%H:%M:%S`" ; read -p "Enter Server(s)"= servertext && echo $servertext > serverlist
 
cat serverlist
for i in `cat serverlist`
do
echo "$i"
 
echo "`date +%D:%H:%M:%S`" ; ssh -t -t $i id $UserID
 
cat /dev/null > serverlist
 
file="`date +%b_%d_%y:%H:%M:%S`"
 
touch $file | mv $file ~/errors/idtoolerrorlogs | cp ~/errors/idtoolerrorlog ~/errors/idtoolerrorlogs/$file
 
~/errors/idtoolerrorlog ~/errors/idtoolerrorlogs/test 
 
 done

Last edited by Scott; 11-29-2011 at 09:25 AM.. Reason: Please use code tags
# 5  
Old 11-29-2011
Code:
echo "`date +%D:%H:%M:%S`" ; ssh -t -t $i id $UserID

You are forcing to allocate tty on remote server for ssh session; have you configured ssh key sharing?

Code:
cat /dev/null > serverlist

What is the point of including this in the loop? I don't see any point of zeroing out a file again and again in a loop.

Code:
touch $file | mv $file ~/errors/idtoolerrorlogs | cp ~/errors/idtoolerrorlog ~/errors/idtoolerrorlogs/$file

Combining commands using pipe!! I have not seen anyone using pipe for this sort of thing. Plus, with this, commands are executed right-to-left. Have you ever considered using "&&" instead?

Code:
~/errors/idtoolerrorlog ~/errors/idtoolerrorlogs/test

I do not see idtoolerrorlog a script file or a binary executable. How do you even expect this to be working? Are you trying to copy the idtoolerrorlog file to test? If yes, where is the cp command in front?

Ohh yes, by some magical way, the code that you posted earlier (pasted below) vanished!! I am wondering why!!
Code:
~/errors/idtoolerrorlog > ~/errors/idtoolerrorlogs/$file 2>&1

No offense buddy, but, the script seems to be pointless and error prone from top to bottom.

Can you tell me what exactly you are trying to do? Maybe I can write the script for you.
# 6  
Old 11-30-2011
I took a look at my script yesterday and I revised it.

!/bin/bash

Linux Script
Code:
 echo "`date +%D:%H:%M:%S`" ; read  -p  " User ID"= UserID

  echo "`date +%D:%H:%M:%S`" ; read -p "Enter Server(s)"= servertext && echo $servertext > serverlist

  cat serverlist
  for i in `cat serverlist`
                        do
         echo "$i"
echo "`date +%D:%H:%M:%S`" ;  ssh -t -t $i id $UserID

 cat /dev/null > serverlist
 
 file="`date +%b_%d_%y:%H:%M:%S`"

 touch $file 

 mv $file ~/errors/idtoolerrorlogs  

~/idtool  2>  ~/errors/idtoolerrorlogs/$file 
 
 
 

                      done

To answer to some of your questions:


Code:
echo "`date +%D:%H:%M:%S`" ; ssh -t -t $i id $UserID

You are forcing to allocate tty on remote server for ssh session; have you configured ssh key sharing?


I don't have rights on the to configure ssh key sharing

Code:
cat /dev/null > serverlist

What is the point of including this in the loop? I don't see any point of zeroing out a file again and again in a loop.

I'm try to delete the contents of serverlist.


What I posted before is what I need help. But if you'd like to build me a new script, please feel free.

---------- Post updated at 01:20 PM ---------- Previous update was at 01:11 PM ----------

Sorry. The script is :



took a look at my script yesterday and I revised it.
Code:
#!/bin/bash

#Linux Script

echo "`date +%D:%H:%M:%S`" ; read -p " User ID"= UserID

echo "`date +%D:%H:%M:%S`" ; read -p "Enter Server(s)"= servertext && echo $servertext > serverlist

cat serverlist
for i in `cat serverlist`
do
echo "$i"
echo "`date +%D:%H:%M:%S`" ; ssh -t -t $i id $UserID

cat /dev/null > serverlist

file="`date +%b_%d_%y:%H:%M:%S`"

touch $file 

mv $file ~/errors/idtoolerrorlogs 

~/idtool 2> ~/errors/idtoolerrorlogs/$file

Last edited by Scott; 12-01-2011 at 02:21 PM.. Reason: Code tags
# 7  
Old 11-30-2011
There is lots of redundancy and pointless things in here.

Code:
#!/bin/bash

#Linux Script

echo "`date +%D:%H:%M:%S`" ; read -p " User ID"= UserID

# You don't need a file.
# echo "`date +%D:%H:%M:%S`" ; read -p "Enter Server(s)"= servertext && echo $servertext > serverlist

echo "`date +%D:%H:%M:%S`"
read -p "Enter Server(s)"= servertext

# Just use the variable itself.  That's what it's there for.
for i in $servertext
do
        echo "$i"
        echo "`date +%D:%H:%M:%S`"
        ssh -t -t $i id $UserID
        file="`date +%b_%d_%y:%H:%M:%S`"

        # You don't need to touch the file.
        # touch $file 
        # You don't need to move the file.
        # mv $file ~/errors/idtoolerrorlogs

        # This is all that's needed.
        ~/idtool 2> ~/errors/idtoolerrorlogs/$file

        # If you want it to append, not overwrite, do this:
        # ~/idtool 2>> ~/errors/idtoolerrorlogs/$file
done
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