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Operating Systems Linux filter data
# 1  
Old 04-07-2011
filter data
hi all,

here is my question.
i have the following data

Block 1
Code:
a    b    c
d    e    f
g    h    i


Block 2
Code:
j    k    l
m    n    o
p    q    r



i need to grep all information from block 1 i.e 'a to i'

should i count the number of row, can somebody help me on this,

thanks
Last edited by Yogesh Sawant; 04-09-2011 at 11:12 AM.. Reason: addded code tags
# 2  
Old 04-07-2011
What is the use of Block 2 ?
# 3  
Old 04-07-2011
Code:
$ ruby -00 -ne 'print if /Block 1/' file

# 4  
Old 04-08-2011
thanks for reply,

well block 1 & 2 are examples, actually i have a very large file container information and i need to filter them by row i have 11 row to filter.
# 5  
Old 04-08-2011
hi

is the pattern you are grepping for always going to start with a and end with i?

Then Please try
Code:
sed '/start point/,/end point/!d' file.txt

ie

Code:
sed '/a/,/i/!d' file.txt

# 6  
Old 04-08-2011
Quote:
Originally Posted by pkabali
hi

is the pattern you are grepping for always going to start with a and end with i?

Then Please try
Code:
sed '/start point/,/end point/!d' file.txt

ie

Code:
sed '/a/,/i/!d' file.txt


no it does not alway start with the same character mentioned.

i want to user the first character or word on the 1st row and count x numbers of row and then print the result
# 7  
Old 04-08-2011
Borrowed this from some post ( sorry cant remember).


For greping/searching and displays a lines before and b lines after context
Code:
  

  nawk 'c-->0;$0~s{if(b)for(c=b+1;c>1;c--)print r[(NR-c+1)%b];print;c=a}b{r[NR%b]=$0}' b=2 a=4 s="string" file1


...where "b" and "a" are the number of lines to print before and after string "s".
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