Linux

Dear all,

This should be simple but I cannot figure it out despite reading all the man pages. Could someone please help me translate this code (GNU date) to one that can be read by BSD date?:

myDate=$(date -d "$h -$l days" +%Y/%m/%d),

where h is a variable of the form DD/MM/YYYY, and l is a simple integer.

So basically, I want to take the date that is stored in h, add l days to it, and format it as YYYY/MM/DD.

Alternatively, is there a way to force my mac to use GNU date instead of BSD date?

Thank you!
Tom

You need to install gnu date for OSX - there is no way to make other date utilities to behave like GNU date

try MacPorts:
The MacPorts Project -- Home

GNU date makes a lot of problems simple to the point any other system feels lacking without it. "How do I translate this date?" "Use GNU date" "I don't have GNU date" "Use this 9-page shell script, then (but not on leap years!)"

Dear all,

Thank you for your replies. I found a solution with BSD date, though admittedly it is not as pretty as with GNU date. I am posting here in case someone finds it useful one day:
GNU version:

Code:

myDate=$(date -d "1/1/1902 +$l days" +%Y/%m/%d)

BDS version:

Code:

myDate=$(date -j -v+"$l"d -f "%m/%d/%Y" "1/1/1902" +"%Y/%m/%d")

Cheers,
Tom