Linux

Ok, so I have this script that was provided to me by one of the posters on this site.

This script seems to be perfect. However, since this is a telnet script, i need to add an if then statement to it but dont know how to do it.

What i want to do is to have this script spit out a certain digit response (0) if telnet is able to connect to machine. If it isn't, i want this script to spit out something else, like a 1 or 2.

I also don't want this script to output anything else but the success or failure response. Meaning, i don't want to see "spawn telnet " command being outputted to the screen.

I apologize if this is asking too much but i desperately need this. Thank you very much guys.

Code:

#!/usr/bin/expect --

set timeout [lindex $argv 0] 
set machine [lindex $argv 1]

spawn telnet $machine

expect {
  "ogin" interact
  timeout  exit 
  }

How about this:

Code:

if [ $? = 0 ];
    then
    echo "Telnet to $machine is possible"
else
    echo "Telnet to $machine failed"
fi

You can replace the echo with some logging construct

---------- Post updated at 10:25 AM ---------- Previous update was at 10:22 AM ----------

Here's a tutorial on how to translate the shell code to what expect wants:

http://floppsie.comp.glam.ac.uk/Glam...ripting/5.html

The logic provided by Mark is the correct one, but you need expect version. For the silent / quiet version of your script, you need "log_user 0" at the top of your script. Change the 0 back to 1 when you need it to become chatty again.
For the script, you can use the following syntax :

Code:

if { $result == "0" } {
    set variable "string"
} elseif { $resul == "1" } {
    set variable "string"
} else {
    puts "Unsupported action or behavior : $result"
    exit 1
}

Thanks, sysgate.

I don't use expect, so rather than mung it up, I gave him the method and a link to the constructs of expect.