HP-UX

Below is a simple script that will find the path were the perl command reside.
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Code:

#!/usr/bin/sh

nPerl=`which perl 2>>/dev/null|grep -v "no perl"`
if [ -z "${nPerl}" ]; then
echo "No Perl application exist..."
else
echo "Existing at $nPerl"
fi

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When I execute this manually, it can find the correct path (/usr/contrib/bin/perl). But if I put it in cron, the value of nPerl is empty. The value returned by "which perl" is "no perl in /usr/bin /usr/sbin ."

Need your expert advise how I will resolve this problem. I haven't encounter any problem with Linux, AIX and Solaris when I execute this via cron.

The PATH variable is not set, the default PATH for cron jobs is:
"/usr/bin:/usr/sbin"

You will have to source /etc/profile or whatever script defines the PATH.

Hi Jim,

Based on your advise, I copied the PATH contained in the /etc/profile and pasted it in the script and it worked fine.

Is there another way of doing it instead of pasting the path in the script since I will deploy the script in several unix/linux servers and I don't want to hard code it? I can imbed in the script to grep the PATH in the /etc/profile but maybe there's another way of implementing it. Thanks.