10 More Discussions You Might Find Interesting
1. UNIX for Beginners Questions & Answers
Hello,
I am running ubuntu 14.04 in a server with 32GB ram.
Due to receiving "high load" errors during ssh connection, I took a look at what's happening from command line. I detected that 20GB of total memory was allocated to a program.
Below you can see some initial part of installation... (4 Replies)
Discussion started by: baris35
4 Replies
2. Red Hat
So we have a RHEL 7.6 workstation with 128 gigs of ram. The OS sees all the ram and 80 cors (40 HT)
We have 1 guest with 8 CPUs and 32gigs of ram running RHEL 7.6 workstation as well. We are trying to create another guest with 64 CPUs and 80 gigs of ram. We setup the system using... (0 Replies)
Discussion started by: joeg1484
0 Replies
3. Solaris
Hi,
the /tmp size is less whereas the size allocated to swap is quite big. how to increase the size of /tmp -
#: swap -l
swapfile dev swaplo blocks free
/dev/md/dsk/d20 85,20 8 273096 273096
#: swap -s
total: 46875128k bytes allocated + 2347188k reserved =... (2 Replies)
Discussion started by: psb74
2 Replies
4. Programming
I want to find the size of the total memory allocated on the heap for the following statement:
int* a = new int;How can I use the sizeof operator for this?
I used:
printf("\t===> %d\n",sizeof(*a));
Is this statement correct?
I have asked the question because when I checked the memory of... (13 Replies)
Discussion started by: rupeshkp728
13 Replies
5. UNIX for Dummies Questions & Answers
Hello,
I need to find the total allocated disk space for the home directory.
How can i find that in unix?(in GB).
Thanks. (4 Replies)
Discussion started by: kailash19
4 Replies
6. Programming
In a 'C' program,when I am trying to allocate memory with the help of malloc () function, it is allocating the memory up to a certain limit for e.g. in my case, it is 670 MB (approx). malloc() returns NULL if I allocate more than this amount of memory.When I tried
to allocate memory in chunks of... (1 Reply)
Discussion started by: vipinsachan
1 Replies
7. Programming
Actually for a process to run it needs text, stack , heap and data segments. All these find a place in the physical memory.
Out of these 4 only heap does exist after the termination of the process that created it. I want to know the exact reason why this happens. Also why the other process need to... (20 Replies)
Discussion started by: karthiktceit
20 Replies
8. AIX
We just set up a system to use large pages. I want to know if there is a command to see how much of the memory is being used for large pages. For example if we have a system with 8GB of RAm assigned and it has been set to use 4GB for large pages is there a command to show that 4GB of the *GB is... (1 Reply)
Discussion started by: daveisme
1 Replies
9. Solaris
Guys,
How to find memory size on solaris zone? We have total 16 GB and have 3 zone, but not sure how to find memory size for each zone? Please help. (1 Reply)
Discussion started by: mokkan
1 Replies
10. Solaris
Hi,
How to find out what is the maximum memory allocated to TOMCAT server in SunOS 5.8?
The Tomcat server crashes down during peak times....
Regards (1 Reply)
Discussion started by: baanprog
1 Replies
POSIX_MEMALIGN(3) Linux Programmer's Manual POSIX_MEMALIGN(3)
NAME
posix_memalign, memalign, valloc - Allocate aligned memory
SYNOPSIS
#include <stdlib.h>
int posix_memalign(void **memptr, size_t alignment, size_t size);
void *memalign(size_t boundary, size_t size);
void *valloc(size_t size);
DESCRIPTION
The function posix_memalign() allocates size bytes and places the address of the allocated memory in *memptr. The address of the allocated
memory will be a multiple of alignment, which must be a power of two and a multiple of sizeof(void *).
The obsolete function memalign() allocates size bytes and returns a pointer to the allocated memory. The memory address will be a multiple
of boundary, which must be a power of two.
The obsolete function valloc() allocates size bytes and returns a pointer to the allocated memory. The memory address will be a multiple
of the page size. It is equivalent to memalign(sysconf(_SC_PAGESIZE),size).
For all three routines, the memory is not zeroed.
RETURN VALUE
memalign() and valloc() return the pointer to the allocated memory, or NULL if the request fails.
posix_memalign() returns zero on success, or one of the error values listed in the next section on failure. Note that errno is not set.
ERRORS
EINVAL The alignment parameter was not a power of two, or was not a multiple of sizeof(void *).
ENOMEM There was insufficient memory to fulfill the allocation request.
NOTES
posix_memalign() verifies that alignment matches the requirements detailed above. memalign() may not check that the boundary parameter is
correct.
POSIX requires that memory obtained from posix_memalign() can be freed using free(). Some systems provide no way to reclaim memory allo-
cated with memalign() or valloc() (because one can only pass to free() a pointer gotten from malloc(), while e.g. memalign() would call
malloc() and then align the obtained value). GNU libc allows memory obtained from any of these three routines to be reclaimed with free().
GNU libc malloc() always returns 8-byte aligned memory addresses, so these routines are only needed if you require larger alignment values.
AVAILABILITY
The functions memalign() and valloc() have been available in all Linux libc libraries. The function posix_memalign() is available since
glibc 2.1.91.
CONFORMING TO
The function valloc() appeared in 3.0 BSD. It is documented as being obsolete in BSD 4.3, and as legacy in SUSv2. It no longer occurs in
SUSv3. The function memalign() appears in SunOS 4.1.3 but not in BSD 4.4. The function posix_memalign() comes from POSIX 1003.1d.
SEE ALSO
malloc(3), free(3), getpagesize(2), brk(2)
GNU
2001-10-11 POSIX_MEMALIGN(3)