HP-UX

Hi,

I'm using IPF hpux machines. I want to know how to get the code name of current processor(say Montecito or Motovale). I have machinfo output like

+++++++++++++++

machinfo
CPU info:
Number of CPUs = 4
Clock speed = 1500 MHz
Bus speed = 400 MT/s
CPUID registers
vendor information = "GenuineIntel"
processor serial number = 0x0000000000000000
processor version info = 0x000000001f020204
architecture revision: 0
processor family: 31 Intel(R) Itanium 2 Family Processors
processor model: 2 Intel(R) Itanium 2 processor
processor revision: 2 Stepping A2
largest CPUID reg: 4
processor capabilities = 0x0000000000000001
implements long branch: 1
Bus features
implemented = 0xbdf0000060000000
selected = 0x0000000040000000
Bus Lock Signal masked

Cache info:
L1 Instruction: size = 16 KB, associativity = 4
L1 Data: size = 16 KB, associativity = 4
L2 Unified: size = 256 KB, associativity = 8
L3 Unified: size = 4096 KB, associativity = 8

Memory = 4084 MB (3.988281 GB)

Firmware info:
Firmware revision = 03.17
FP SWA driver revision: 1.18
IPMI is supported on this system.
ERROR: Unable to obtain manageability firmware revision info.

Platform info:
model string = "ia64 hp server rx4640"
machine id number = bba1db48-8942-11da-8445-d679158b683a
machine serial number = SGH45494SE

OS info:
sysname = HP-UX
nodename = jlab01
release = B.11.23
version = U (unlimited-user license)
machine = ia64
idnumber = 3147946824
vmunix _release_version:
@(#) $Revision: vmunix: B11.23_LR FLAVOR=perf Fri Aug 29 22:35:38 PDT 2003 $

+++++++++++

I do not know how to map the processor information to the code name.

Thanks in advance.

Itanium - Wikipedia, the free encyclopedia maybe?

---------- Post updated at 16:18 ---------- Previous update was at 16:08 ----------

Forgot...
Because of the speed, it looks like a "Madison"...