Using While and If statements

 
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Homework and Emergencies Homework & Coursework Questions Using While and If statements
# 8  
Old 01-12-2011
Quote:
Originally Posted by methyl
@jjb1989
What Shell do you use?
Code:
echo $SHELL

I use BASH Smilie
# 9  
Old 01-12-2011
I don't write pure bash and I don't think we have seen your code to populate the array. Might be worth posting that script.
Remember that array elements are numbered from zero. In your case zero to six (i.e. seven elements).
Here's a bit of test code to get you started on how to walk the array and how to refer to the elements in shell script. You will need to change variable names to match the rest of your script and maybe change "echo" to "printf" depending on what you have been taught.

The idea is to build your script in simple stages and test each stage.
Once you can read back you array of the seven numbers the user typed you are in a position to insert code to do more (like find the highest value). Finding the median will be interesting.

Code:
echo "Read back test array in the same order it was created"
counter=0
counter_max=6
while [ ${counter} -le ${counter_max} ]
do
        echo "Array element ${counter} = ${num_array[${counter}]}"
        counter=$((counter+1))
done

# 10  
Old 01-15-2011
Clearer:

Code:
#!/bin/bash

# Array
declare -a numeros=(
	$(
		for i in $(seq 1 1 7)
		do 
			echo -e `expr ${RANDOM} % 100`
		done
	)
);
# Integer variable
declare -i i=0;
mayor=${numeros[0]}

while [ $i -lt $[ ${#numeros[*]} - 1] ]
do
	echo -e "numeros[$i] = ${numeros[$i]}"
	if [ ${numeros[$i]} -gt $mayor ]
	then
		mayor=${numeros[$i]}
	fi
	((i++));
done

echo -e "Mayor : ${mayor}";


Code:
#!/bin/bash
# fill array:
declare -a numeros=($(for i in $(seq 1 1 8); do echo -e `expr ${RANDOM} % 100`; done));
# Integer variable
declare -i i=0;

echo -e "Array : ${numeros[*]}";
if expr ${#numeros[@]} % 2 &> /dev/null
then
	# sort tmp array:
	tmp=(`echo -en "${numeros[*]}" | tr ' ' '\n' | sort -n`);
	echo -e "Sort Array : ${tmp[*]}";
	echo -e "Median : ${tmp[`expr ${#tmp[@]} / 2`]}";	
else
	tmp=(`echo -en "${numeros[*]}" | tr ' ' '\n' | sort -n`);
	echo -e "Sort Array : ${tmp[*]}";
	echo -en "Mediana : ";
	echo -e $(( ${tmp[ `expr \( ${#tmp[*]} / 2 \) - 1` ]} + ${tmp[ `expr ${#tmp[*]} / 2` ]} )) / 2 | bc -l
fi


Last edited by Leo Gutierrez; 01-15-2011 at 01:57 AM..
# 11  
Old 01-21-2011
Wow, some of the above examples defy simplicity to the nth+1 degree.
Code:
#!/bin/bash
let count=0
let largest=-999999
while read input; do
    let number[$count]=$input;
    if [ $input -gt $largest ] ; then
         let largest=$input;
    fi;
    let  sum=sum+number
    let count=count=+1
done

The trouble I have difficulty with is "finding median with an if statement". BASH doesn't deal with floating point, so I'm not sure how to accomplish this. We could use sort but that would obviate the need for an if clause. We could iteratively throw away the highest and lowest values, but that's a lot of work (computationally).

Last edited by otheus; 01-21-2011 at 08:49 PM.. Reason: major syntax errores
# 12  
Old 01-21-2011
Quote:
Originally Posted by otheus
The trouble I have difficulty with is "finding median with an if statement". BASH doesn't deal with floating point, so I'm not sure how to accomplish this.
If we can assume that the seven numbers contain no duplicates, the median is the number with exactly 3 numbers larger than it. This entails a double while loop and at least 2 if's, but no floating point is needed.
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