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if you want to check the size of subdirectories under a directory, then it will be better to to check the size of parent directory, for parent directory run this command,

Code:

du -k /home/vipin/data

(data is the directory,that i want to check the size ).

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@vipinkumarr
Your "du" command does not match the requirement. The O/P posted the correct "du" command in post #1 but was looking for something faster.
Also this thread went cold a month ago. Please look at at the date on threads and read any other solutions before posting.

On topic:
I don't think that the O/P posted how many files there were in this directory. On poster suggested creating a separate filesystem which was a good idea because this would also defragment the directory files in the process.

After applying so many option i find the solution to save the time.
let say i have /home/vipin/ (size of vipin dir is 5GB)
then

Code:

cd /home/vipin/
du -ha >tempfile &

(temp file is temporary file)(command will run in the background)
Hence the command is running in background you can do some other works.
Its not a permanent solution but I think it can help you..

Code:

cd /home/vipin/
du -ha >tempfile &

This command is totally unsuitable because it outputs the size of every file instead of just the total.
As pointed out after your last post, the correct command is in Post #1 .

otheus: "...Don't use find with exec unless you have to do stuff inside the exec!"

Well, he was executing "ls -ltr" 'inside the exec', wasn't he?

What is so bad about using the '-exec' with the 'find' command?

Well, it's often redundant and can multiply the amount of time needed drastically. That would run ls thousands of times, for one thing, when find's own features may have been able to do an ls of sorts by itself, avoiding the need to create thousands of processes. I'm uncertain if sun find supports -printf, however.