AIX

Is there a way to find out the path/name of a script file that signaled my process? All that shows up from the signal info data is ksh. Even in getprocs64 is is just ksh. I am not sure why the full path and file name are not showing up instead of the shell name. I tried ptrace64 with PT_LDINFO but cannot get past and EBADF error. So, any suggestions would be appreciated.

Your invoker is the pid in $PPID, and you can run ps in a popen() or something C library equivalent to find out about it. The second parameter is the script. The effect of starting a script with the line:

Code:

#!<path_to_interpreter> [ optional_one_arg ]

is that exec() effectively executes a command:

Code:

<path_to_interpreter> [ optional_one_arg ] $@

The optional_one_arg is nice with things like sed that need -f to make it work. See man exec or run "truss -fae <some_script>" or the like.

Thanks DG, but I am not looking for my invoker, I already know that one. I am looking for the name of the script file that sent me a signal 15. We have several scripts that look for my specific process to send it a signal via "kill" in AIX and I need to find the name of the one that sent it to me. Is this information lost? I have tried "ps" and "getprocs64" but they both have just "ksh" as the description of the process.

I know we could probably change our scripts to write a file or something which I could then look for, but I am trying to make the change in one place.

Right, signalled, sorry, so you have the pid, the ps command will do it but you need to ask for the entire command line with "-o args" or "-f".

Thanks DG, that did it. I appreciate the help. I forgot ps won't display the whole description without -f.