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weird korn shell script

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# 1  
Old 07-12-2010
Question weird korn shell script
here is the one of the scripts:

script1.ksh
Code:
function haha
{
  print "calling haha"
  exit
}

script2.ksh
Code:
. script1.ksh
haha | tee -a /dev/null
print "i am script 2"

after launching the script2, the result:
---------------------------------------------
Code:
calling haha
i am script 2

would be presented, could someone please tell me why the "exit" statement NOT working properly?
Last edited by pludi; 07-12-2010 at 04:01 AM.. Reason: code tags, please...
# 2  
Old 07-12-2010
Because you are sending the output to null. just remove the pipe and tee cmd and you will get it

script1.ksh
Code:
function haha
{
  print "calling haha"
  exit
}

script2.ksh
Code:
. script1.ksh
haha 
print "i am script 2"

# 3  
Old 07-12-2010
thanks for your reply, and what you pointed is what i want to know, could you give me a hint please
# 4  
Old 07-12-2010
tee command can be placed anywhere in a pipe to check what the output looks like at a certain point. So basically you have directed the output of function haha to a file instead of standard output and thus the execution of rest of the commands continues as normally
# 5  
Old 07-12-2010
due to the pipe line, the function ran in a sub (child) process so the "exit" only exited the sub process.
This User Gave Thanks to binlib For This Post:
getter
# 6  
Old 07-12-2010
I agree with binlib.

if you combine the two scripts the "exit" will behave as you expect.

Code:
#!/bin/ksh
#script2.ksh
function haha
{
  print "calling haha"
  exit
}

haha 
print "i am script 2"

./script2.ksh
calling haha

# 7  
Old 07-14-2010
thanks for all~!!!
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