02-20-2006
Sending output to a file
Hi All,
read dif
echo `date +%Y%m%d`|./add $dif|./fmtdt %mon%dd
The above script is for adding days to current date to find the new date. This script divides the current date into 20060220(YYYYMMDD) format and pass this output to add script. The add script will add the days to the current date and will produce output in the YYYYMMDD format 20060225.The fmtdt will produce the output in the Mon dd(Feb 20) format.
The output will be Feb 25 (if input is 5 and current date is Feb 20)
The output of the above script should be passed to a variable and the variable should be printed like /Feb 25/ (add this front and back print)
Question
1. How to pass the output to a variable (ex ouput: Feb 20)
2. Then how to print the variable in the following format /Feb 20/
I am new to Shell scripting.Please help me.Please answer ASAP(URGENT).
Thanks in advance.
Note:
Is there anyway to pass this output to file and cat that file and pass this to a variable.
I did like this
echo `date +%Y%m%d`|./add $dif|./fmtdt %mon%dd > date_file (Succeeded-The file is created with output)
a= cat date_file(Failed to assign the value to a file
I succeeded in passing the output to file and cat that file .But failed to assign that value to a Variable.Please Guide me
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LEARN ABOUT PHP
datetime.format
DATETIME.FORMAT(3) 1 DATETIME.FORMAT(3)
DateTime::format - Returns date formatted according to given format
Object oriented style
SYNOPSIS
public string DateTime::format (string $format)
DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format)
Procedural style
string date_format (DateTimeInterface $object, string $format)
Returns date formatted according to given format.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3)
o $format
- Format accepted by date(3).
RETURN VALUES
Returns the formatted date string on success or FALSE on failure.
EXAMPLES
Example #1
DateTime.format(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
echo date_format($date, 'Y-m-d H:i:s');
?>
The above example will output:
2000-01-01 00:00:00
NOTES
This method does not use locales. All output is in English.
SEE ALSO
date(3).
PHP Documentation Group DATETIME.FORMAT(3)