Sponsored Content
Full Discussion: doubt in cal command
Operating Systems AIX doubt in cal command Post 97201 by sumi on Friday 27th of January 2006 04:50:16 AM
Old 01-27-2006
i am using datecalc function....after subtracting 6 from dt1, i am getting
2006 1 15

dt1=2006 01 27
datecalc -a $dt1 - 6

but i want the output as
2006 01 15

i searched the forum... if i get the "day" individually and perform operation, i can use typedef. but i am using the full date and subtracting 6 from it. how to get the desired output as above?
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Cal command

I am trying to configure the cal command to recognize the month names. When you type: cal - you get the calander for the current month of the current year. Is there a way of making the system recognize March, and Mar. So I could type: cal March or cal mar and get the same response as cal.... (5 Replies)
Discussion started by: Astudent
5 Replies

2. Shell Programming and Scripting

Julian Dates and the Cal command

hey all, I was wondering if it was possible to get the julian date with the cal command. I know that the "-j" option will display it, however, i need the Julian Date of a specific date, in number. For example, the User would enter their age like 19800101 or YYYMMDD, like so. This info... (0 Replies)
Discussion started by: shan2on
0 Replies

3. UNIX for Dummies Questions & Answers

cal command display issues

I am using AIX version 5.3 I like the cal function because I can print a nice concise view of the calendar for the whole year. I want the calendar to display with 3 months across instead of 2, which is what is happening. My terminal display is set with 67 rows and 140 columns so that should... (0 Replies)
Discussion started by: ruddydaggerwing
0 Replies

4. Shell Programming and Scripting

parsing return from cal command

Jim , Anyone I do not have GNU date Besides I am particularly interested in how one can parse the return from the cal command. Say do - cal 11 2008 - and parse out a given date, say the 8th and return that the 8th was Saturday. ( diffrentiating between S for Saturday and Sunday , also in the case... (1 Reply)
Discussion started by: dragrid
1 Replies

5. UNIX for Dummies Questions & Answers

cal command

Hello, I wanted to display calender for the previou, current and next month in a single command... I used the command cal -3 for this. But its throwing me a Bad Argument error. I am using HP UX to execute this command. Is this a syntax error, or let me know if there any other ways to... (6 Replies)
Discussion started by: atlantis
6 Replies

6. Shell Programming and Scripting

another cal command question.

I got this from this board yesterday cal | xargs -n1 | tail -1 which displays the current months days.. for instance if you type this in a shell today you will get 31. I would like to also display the month and year.. something like March 2011 has 31 days. how would I do that? ... (3 Replies)
Discussion started by: rontopia
3 Replies

7. Shell Programming and Scripting

Modify cal command in shell script

Plz help me To modify "cal " command to display calenders of the specified months. $ cal jan....oct (0 Replies)
Discussion started by: shivasaini
0 Replies

8. Shell Programming and Scripting

Modify cal command in shell script

Plz help me a) To display on the screen the sorted output of "who" along with the total no. of users. b) the same output (except the no. of users) should be in file FILE1. (2 Replies)
Discussion started by: shivasaini
2 Replies

9. UNIX for Dummies Questions & Answers

Cal command in UNIX

modify "cal " command to display calenders of the specified months. $ cal jan....aug (1 Reply)
Discussion started by: ssaini
1 Replies

10. UNIX for Dummies Questions & Answers

Cal command to display 5 months ?

Hi, I'm curious to know if we can display 5 months of a calendar using the cal command. I know we can three successive months (cal -3) but I wanted to know if we can do it with 5 months for example. (Give a specific month, and get as a result two previous months + the month in question + two... (12 Replies)
Discussion started by: Imane
12 Replies
DATETIME.MODIFY(3)							 1							DATETIME.MODIFY(3)

DateTime::modify - Alters the timestamp

       Object oriented style

SYNOPSIS
public DateTime DateTime::modify (string $modify) DESCRIPTION
Procedural style DateTime date_modify (DateTime $object, string $modify) Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3). PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $modify -A date/time string. Valid formats are explained in Date and Time Formats. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.6 | | | | | | | Absolute date/time statements now take effect. | | | Previously, only relative parts were used. | | | | | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.modify(3) example Object oriented style <?php $date = new DateTime('2006-12-12'); $date->modify('+1 day'); echo $date->format('Y-m-d'); ?> Procedural style <?php $date = date_create('2006-12-12'); date_modify($date, '+1 day'); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2006-12-13 Example #2 Beware when adding or subtracting months <?php $date = new DateTime('2000-12-31'); $date->modify('+1 month'); echo $date->format('Y-m-d') . " "; $date->modify('+1 month'); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-01-31 2001-03-03 SEE ALSO
strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes- tamp(3). PHP Documentation Group DATETIME.MODIFY(3)
All times are GMT -4. The time now is 01:12 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy