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Full Discussion: doubt in cal command
Operating Systems AIX doubt in cal command Post 96775 by Perderabo on Monday 23rd of January 2006 11:43:43 AM
Old 01-23-2006
Read the date arithmetic article in our faq section. My datecalc script can do stuff like this:
Code:
#! /usr/bin/ksh

desiredday=$1
year=$2

(( cday = $(datecalc -j $year 1 1) + (($desiredday - $(datecalc -d $year 1 1) + 7)%7) ))
(( limit = $(datecalc -j $year 12 31) ))
while ((cday<limit)) ; do
        datecalc -j $cday
        ((cday=cday+7))
done
exit 0

The first argument is the day of the week (0 - 6) and the second argument is the year.
./script 6 2006 will give you all saturdays for the current year.
 

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