Sponsored Content
Full Discussion: Unix Date query
Top Forums UNIX for Advanced & Expert Users Unix Date query Post 9528 by Kelam_Magnus on Monday 29th of October 2001 12:11:36 PM
Old 10-29-2001
date?

maybe you could give us some more info on what you are doing.

That may help us give you the answer.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Date change related query

Good day folks, This is my first post on this board and I thank you in advance for helping me with this issue. Any idea how I can synchronize server time with another timeserver but have my server lag behind by 2 seconds? Meaning...I need a simple unix script that I can run as crone that... (2 Replies)
Discussion started by: franklo
2 Replies

2. Shell Programming and Scripting

Date & NUmber Validation Query

Hi Do you have any pointers how to validate numbers (not to contain alphabets and special characters) and date(MM/DD/YYYY) format. I used following regular expression to validate integer, which is not working in the default shell: nodigits="$(echo $testvalue | sed 's/]//g')" ... (4 Replies)
Discussion started by: alok_jax
4 Replies

3. Shell Programming and Scripting

Compare date from db2 table to yesterday's Unix system date

I am currently running the following Korn shell script which works fine: #!/usr/bin/ksh count=`db2 -x "select count(*) from schema.tablename"` echo "count" I would like to add a "where" clause to the 2nd line that would allow me to get a record count of all the records from schema.tablename... (9 Replies)
Discussion started by: sasaliasim
9 Replies

4. Shell Programming and Scripting

Query regarding date field in shell script

Hi, I wrote a simple shell script which accepts the input value yearmonth in the format YYYYMM and displays the date as YYYY-MM-DD.Day will be 01 always.Please find the code below #!/bin/ksh export yearmonth_date=$1 print_usage() { echo "usage: ${0##*/} <yearmonth_date> \n" \ ... (1 Reply)
Discussion started by: kavithakuttyk
1 Replies

5. Shell Programming and Scripting

Convertion of Date Format using SQL query in a shell script

When I write Select date_field from TableA fetch first row only I am getting the output as 09/25/2009. I want to get the output in the below format 2009-09-25 i.e., MM-DD-YYYY. Please help (7 Replies)
Discussion started by: dinesh1985
7 Replies

6. UNIX for Dummies Questions & Answers

Date Query

I need to generate a report on the first of each month that will show me how many points are going to expire on a particular scheme for the next three months. The points expiry is not an issue what I have an issue with is finding the command to give me the last day of each month for the current and... (2 Replies)
Discussion started by: theref
2 Replies

7. Shell Programming and Scripting

Query - date command

Hi, I am trying to capture the total run time of a script which contains SQL's by providing date command in top & bottom, it displaying both the times same in top & bottom.However the time in the sql connection is different.Please help. OS - LINUX Shell - ksh printf "Script Started at... (3 Replies)
Discussion started by: nag_sathi
3 Replies

8. Shell Programming and Scripting

UNIX date fuction - how to deduct days from today's date

Hi, One of my Unix scripts needs to look for files coming in on Fridays. This script runs on Mondays. $date +"%y%m%d" will give me today's date. How can I get previous Friday's date.. can I do "today's date minus 3 days" to get Friday's date? If not, then any other way?? Name of the files is... (4 Replies)
Discussion started by: juzz4fun
4 Replies

9. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies

10. UNIX for Beginners Questions & Answers

UNIX script to replace old date with current date dynamically in multiple files present in a folder

I am trying to work on a script where it is a *(star) delimited file has a multiple lines starts with RTG and 3rd column=TD8 I want to substring the date part and I want to replace with currentdate minus 15 days. Here is an example. iam using AIX server $ cat temp.txt RTG*888*TD8*20180201~... (1 Reply)
Discussion started by: Shankar455
1 Replies
CALENDAR(3)						   BSD Library Functions Manual 					       CALENDAR(3)

NAME
easterg, easterog, easteroj, gdate, jdate, ndaysg, ndaysj, week, weekday -- Calendar arithmetic for the Christian era LIBRARY
Calendar Arithmetic Library (libcalendar, -lcalendar) SYNOPSIS
#include <calendar.h> struct date * easterg(int year, struct date *dt); struct date * easterog(int year, struct date *dt); struct date * easteroj(int year, struct date *dt); struct date * gdate(int nd, struct date *dt); struct date * jdate(int nd, struct date *dt); int ndaysg(struct date *dt); int ndaysj(struct date *dt); int week(int nd, int *year); int weekday(int nd); DESCRIPTION
These functions provide calendar arithmetic for a large range of years, starting at March 1st, year zero (i.e., 1 B.C.) and ending way beyond year 100000. Programs should be linked with -lcalendar. The functions easterg(), easterog() and easteroj() store the date of Easter Sunday into the structure pointed at by dt and return a pointer to this structure. The function easterg() assumes Gregorian Calendar (adopted by most western churches after 1582) and the functions easterog() and easteroj() compute the date of Easter Sunday according to the orthodox rules (Western churches before 1582, Greek and Russian Orthodox Church until today). The result returned by easterog() is the date in Gregorian Calendar, whereas easteroj() returns the date in Julian Calendar. The functions gdate(), jdate(), ndaysg() and ndaysj() provide conversions between the common "year, month, day" notation of a date and the "number of days" representation, which is better suited for calculations. The days are numbered from March 1st year 1 B.C., starting with zero, so the number of a day gives the number of days since March 1st, year 1 B.C. The conversions work for nonnegative day numbers only. The gdate() and jdate() functions store the date corresponding to the day number nd into the structure pointed at by dt and return a pointer to this structure. The ndaysg() and ndaysj() functions return the day number of the date pointed at by dt. The gdate() and ndaysg() functions assume Gregorian Calendar after October 4, 1582 and Julian Calendar before, whereas jdate() and ndaysj() assume Julian Calendar throughout. The two calendars differ by the definition of the leap year. The Julian Calendar says every year that is a multiple of four is a leap year. The Gregorian Calendar excludes years that are multiples of 100 and not multiples of 400. This means the years 1700, 1800, 1900, 2100 are not leap years and the year 2000 is a leap year. The new rules were inaugurated on October 4, 1582 by deleting ten days following this date. Most catholic countries adopted the new calendar by the end of the 16th century, whereas others stayed with the Julian Calendar until the 20th century. The United Kingdom and their colonies switched on September 2, 1752. They already had to delete 11 days. The function week() returns the number of the week which contains the day numbered nd. The argument *year is set with the year that contains (the greater part of) the week. The weeks are numbered per year starting with week 1, which is the first week in a year that includes more than three days of the year. Weeks start on Monday. This function is defined for Gregorian Calendar only. The function weekday() returns the weekday (Mo = 0 .. Su = 6) of the day numbered nd. The structure date is defined in <calendar.h>. It contains these fields: int y; /* year (0000 - ????) */ int m; /* month (1 - 12) */ int d; /* day of month (1 - 31) */ The year zero is written as "1 B.C." by historians and "0" by astronomers and in this library. SEE ALSO
ncal(1), strftime(3) STANDARDS
The week number conforms to ISO 8601: 1988. HISTORY
The calendar library first appeared in FreeBSD 3.0. AUTHORS
This manual page and the library was written by Wolfgang Helbig <helbig@FreeBSD.org>. BUGS
The library was coded with great care so there are no bugs left. BSD
November 29, 1997 BSD
All times are GMT -4. The time now is 09:49 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy