10-29-2001
Thankyou very much for your help! My only outstanding query involves the allocation of a PID to UNIX processes:
Is it simply a case of UNIX maintaining a pool of 'free' PIDs, and then allocating a free PID when a process is run by a user. Conversely, the PID of a terminated process is returned to the 'free' pool ready for another process to receive?
I presume that at any point in time on the UNIX machine, no 2 processes will have the same PID?
Thanks!
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LEARN ABOUT REDHAT
setsid
SETSID(2) Linux Programmer's Manual SETSID(2)
NAME
setsid - creates a session and sets the process group ID
SYNOPSIS
#include <unistd.h>
pid_t setsid(void);
DESCRIPTION
setsid() creates a new session if the calling process is not a process group leader. The calling process is the leader of the new session,
the process group leader of the new process group, and has no controlling tty. The process group ID and session ID of the calling process
are set to the PID of the calling process. The calling process will be the only process in this new process group and in this new session.
RETURN VALUE
The session ID of the calling process.
ERRORS
On error, -1 will be returned. The only error which can happen is EPERM. It is returned when the process group ID of any process equals
the PID of the calling process. Thus, in particular, setsid fails if the calling process is already a process group leader.
NOTES
A process group leader is a process with process group ID equal to its PID. In order to be sure that setsid will succeed, fork and exit,
and have the child do setsid().
CONFORMING TO
POSIX, SVr4.
SEE ALSO
setpgid(2), setpgrp(2)
Linux 1.0.0 1994-08-27 SETSID(2)